Question

我放弃了，我只是想知道为什么push_back没有按预期工作。忘记我的代码有多糟糕或过于复杂。

我有一个python程序，它读取缓冲区，并从列表中逐行显示。如果最后一行未完成，请将其从列表中删除，并在下一次迭代时将其预先附加到缓冲区。

response += s.recv(1024).decode("utf-8")
    if response[-1] != '\n':
        lines = response.splitlines()
        response = lines[-1]
        lines = lines[:-1]
    else:
        lines = response.splitlines()
        response = '';

for line in lines:
    print("New Line:   " + line)

time.sleep(1)

以＆＃34; New Line＆＃34;为前缀所以我可以看到我的＆＃34;行＆＃34;

中没有隐藏多行

这是输出：

New Line:   :tmi.twitch.tv 001 k20stitchbot :Welcome, GLHF!
New Line:   :tmi.twitch.tv 002 k20stitchbot :Your host is tmi.twitch.tv
New Line:   :tmi.twitch.tv 003 k20stitchbot :This server is rather new
New Line:   :tmi.twitch.tv 004 k20stitchbot :-
New Line:   :tmi.twitch.tv 375 k20stitchbot :-
New Line:   :tmi.twitch.tv 372 k20stitchbot :You are in a maze of twisty passages, all alike.
New Line:   :tmi.twitch.tv 376 k20stitchbot :>
New Line:   :tmi.twitch.tv CAP * ACK :twitch.tv/membership

所以我用C ++编写了以下用C ++编写的以下内容：

    found = start = end = 0;
    iResult = recv(ConnectSocket, recvbuf, recvbuflen - 1, 0);

    if (iResult > 0)
    {
        recvbuf[iResult] = '\0';
        newString.append(recvbuf);
        std::replace(newString.begin(), newString.end(), '\r', ' ');
        end = newString.length();

        while ((found = newString.find("\n", start)) != -1) {
            myList.push_back(newString.substr(start, found));
            start = found + 1;
            if (start >= end) {
                start = end;
            }
            Sleep(1000);
        }

        if (newString.back() != '\n')
        {
            std::string leftOver = newString.substr(start, end);
            newString = leftOver;
        }
        else 
        {
            newString = "";
        }

        for (myListIt = myList.begin(); myListIt != myList.end(); myListIt++)
        {
            cout << "New Line: " << *myListIt << "\n";
        }

        myList.clear();
    }

我的输出不太理想，它几乎就好像不是从开始推到列表中，而是从头到尾推动。

New Line: :tmi.twitch.tv 001 k20stitchbot :Welcome, GLHF!
New Line: :tmi.twitch.tv 002 k20stitchbot :Your host is tmi.twitch.tv
:tmi.twitch.tv 003 k20stitchbot :This server is
New Line: :tmi.twitch.tv 003 k20stitchbot :This server is rather new
:tmi.twitch.tv 004 k20stitchbot :-
:tmi.twitch.tv 375 k20stitchbot :-
:tmi.twitch.tv 372 k20stitchbot :You
New Line: :tmi.twitch.tv 004 k20stitchbot :-
:tmi.twitch.tv 375 k20stitchbot :-
:tmi.twitch.tv 372 k20stitchbot :You are in a maze of twisty passages, all alike.
:tmi.twitch.tv 376 k20stitchbot :>

New Line: :tmi.twitch.tv 375 k20stitchbot :-
:tmi.twitch.tv 372 k20stitchbot :You are in a maze of twisty passages, all alike.
:tmi.twitch.tv 376 k20stitchbot :>

New Line: :tmi.twitch.tv 372 k20stitchbot :You are in a maze of twisty passages, all alike.
:tmi.twitch.tv 376 k20stitchbot :>

New Line: :tmi.twitch.tv 376 k20stitchbot :>

Answer 1

子串参数是：begin-position，length
而不是：开始位置，结束位置

在c ++中推送到列表时有趣的行为

1 个答案: