Question

所以我一直在尝试文件输入和输出来保存Yugioh的名单，我在大多数情况下都能使用它。我使用deques来存储一个名为Card的类对象，其中包含所有信息，还有一个Deck类来为每种类型的deck，main，side和extra保存Card对象的deques。

所以无论如何，关于这个问题。我使用本地双端队列来保存以前加载的卡片的信息，因为当我加载每张卡片时，我搜索deque以获得完全匹配，然后将数字存储在变量中以用于输出。当我尝试添加到这个称为“已处理”的本地双端队列时，我收到错误。

调试断言失败！表达式：deque迭代器不可解除引用

void Deck::SaveDeck(std::string filename)
{
    std::ofstream outFile;
    outFile.open(filename.c_str());

    //send the file the deck name
    outFile << this->deckName << "\n";

    //send the deck sizes
    outFile << main_deck_size << " " << side_deck_size << " " << extra_deck_size << "\n";

    //iterator to iterate through the entire deck looking for copies
    std::deque<Card>::iterator iter = main_deckCards.begin();
    std::deque<Card>::iterator iter2 = main_deckCards.begin();

    //deque to hold previously added cards
    std::deque<Card> processed;
    std::deque<Card>::iterator processed_iter = processed.begin();

    string setNAME = "";
    int setNum = 0;
    int quantity = 0;
    bool is_processed = false;

    for (int i = 0; i < main_deck_size; i++)
    {
        //reset processed flag
        is_processed = false;

        //check processed queue for exact card
        for (int j = 0; j < processed.size(); j++)
        {
            if (iter[i].SET_NAME == processed_iter[j].SET_NAME && iter[i].SET_NUM == processed_iter[j].SET_NUM)
            {
                is_processed = true;
                break;
            }
        }

        if(is_processed == false)
        {
            //reset variables
            setNAME = "";
            setNum = 0;
            quantity = 0;

            //draw from the next card
            setNAME = iter[i].SET_NAME;
            setNum = iter[i].SET_NUM;
            quantity++;

            //loop to look for similar cards
            for (int x = i+1; x < main_deck_size; x++)
            {
                if (iter2[x].SET_NAME == setNAME && iter2[x].SET_NUM == setNum)
                {
                    quantity++;
                }
            }

            outFile << setNAME << " " << setNum << " " << quantity << "\n";

            if(setNAME == "LOB-EN")
            {
                //removing this line causes the program to work
                processed.push_back(LOB[setNum]);
            }
        }
    }
}

删除我试图将对象放入双端队列的行，程序运行没有错误，除了它多次写入相同的卡片，我想处理每个卡片的数量而不是倍数的文件出现在不同的路线上。我已经检查了其他问题，问题是由于尝试在空双端队列中使用std :: deque :: pop_front / back。但我根本不打电话给pop_front /。

关于可能导致错误的任何想法？

Answer 1

使用processed.push_back(LOB[setNum]);可能会使processed_iter无效。

在循环的第一轮中，当processed开始为空时，失效或多或少得到保证。

Deque迭代器不可解除引用

1 个答案: