在openshift中使用快速js上传图片并获取上传图片的网址

Question

我正在快递中处理用户个人资料，我需要上传用户图片。我已经搜索了很多，但没有得到很多关于此的信息。

所以这是迄今为止我所做的。 我的个人资料查看代码： -

 <form method="post" name="profileform" class="profileform" enctype="multipart/form-data" action="">
    <div class="form-group">
     <label for="UserProfilePicture">Profile Picture:</label>
     <input type="file" class="form-control" id="UserProfilePicture" class="UserProfilePicture disbalefield" name="file"  placeholder="Click to add Profile Pic"></div> 
     <input type="submit" value="Submit" class="btn btn-default" class="userprofilesubmit" id="userprofilesubmit" />
    </form>

这是我的server.js代码

app.use('/uploads', express.static(process.env.OPENSHIFT_DATA_DIR+'/uploads'));
app.use(express.limit('5mb'));

app.use(bodyParser.json());
app.use(bodyParser.urlencoded({ extended: true }));
app.post('/profile', function(req, res){
if(!req.session.logged_in){
    res.redirect('/login');
}
console.log("dsadsa");
  // Get the temporary location of the file
var tmp_path = req.files.file.path;
// Set where the file should actually exists - in this case it is in the "images" directory.
var target_path = process.env.OPENSHIFT_DATA_DIR + '/uploads/' + req.files.file.name;


// Move the file from the temporary location to the intended location
fs.rename(tmp_path, target_path, function(err) {
    if (err){
        throw err;
    }

    // Delete the temporary file, so that the explicitly set temporary upload dir does not get filled with unwanted files.
    fs.unlink(tmp_path, function() {
        if (err){
            throw err;
        }
        //
        console.log("reached");
            res.send("uploaded");
    });
});


});

对缩进感到抱歉。任何帮助将受到高度赞赏。