将一系列单元格转换为字符串的最佳方法是什么? 我有一个函数只接受一个字符串作为输入所以我需要将范围转换为字符串,同时保留尽可能多的格式(即它需要看起来像一个表或列表,而不仅仅是一串字符) 。 我尝试过使用CStr(),以及从一个范围转换为一个数组然后转换为一个字符串,但我只是得到了错误。
编辑:代码尝试
Dim email_answer As Integer
email_answer = MsgBox("Do you want to be emailled a copy of this schedule?", vbYesNo)
If email_answer = vbYes Then
Dim wb As Workbook
Dim to_send As Range
to_send = Range("D3", "D10")
If Val(Application.Version) < 14 Then Exit Sub
Set wb = ActiveWorkbook
With wb
MailFromMacWithMail body content:=CStr(to_send), _
mailsubject:="Schedule", _
toaddress:="email address", _
ccaddress:="", _
bccaddress:="", _
attachment:=.FullName, _
displaymail:=False
End With
Set wb = Nothing
End If
答案 0 :(得分:6)
要在范围内以逗号分隔的单元格值列表:
Function RangeToString(ByVal myRange as Range) as String
RangeToString = ""
If Not myRange Is Nothing Then
Dim myCell as Range
For Each myCell in myRange
RangeToString = RangeToString & "," & myCell.Value
Next myCell
'Remove extra comma
RangeToString = Right(RangeToString, Len(RangeToString) - 1)
End If
End Function
如果行号增加,您可以添加额外的功能,例如插入分号而不是逗号。
使用此功能:
Sub AnySubNameHere()
Dim rng As Range
Set rng = ActiveSheet.Range("A3:A10")
Dim myString as String
myString = RangeToString(rng)
End Sub
答案 1 :(得分:5)
你可以使用这个功能:
Function Rang2String(rng As Range) As String
Dim strng As String
Dim myRow As Range
With rng
For Each myRow In .Rows
strng = strng & Join(Application.Transpose(Application.Transpose(myRow.value)), "|") & vbLf
Next
End With
Rang2String = Left(strng, Len(strng) - 1)
End Function
将返回带换行符的字符串作为范围行分隔符和管道(&#34; |&#34;)作为列分隔符
答案 2 :(得分:1)
我知道这个问题已经差不多一年了,但我找到了一个适合我的快速解决方案: 您必须创建对Microsoft Forms 2.0对象库的引用才能使用DataObject。
Public Function GetStringFromRange(RNG As Range) As String
Dim DOB As New MSForms.DataObject
RNG.Copy
DOB.GetFromClipboard
GetStringFromRange = DOB.GetText
End Function
答案 3 :(得分:0)
这些功能中的任何一个都能为您完成。
Function ConCatRange2(CellBlock As Range) As String
'for non-contiguous cells =ccr((a1:a10,c4,c6,e1:e5))
Dim Cell As Range
Dim sbuf As String
For Each Cell In CellBlock
If Len(Cell.Text) > 0 Then sbuf = sbuf & Cell.Text & ","
Next
ConCatRange2 = Left(sbuf, Len(sbuf) - 1)
End Function
OR
Function mergem(r As Range) As String
mergem = r.Cells(1, 1).Value
k = 1
For Each rr In r
If k <> 1 Then
mergem = mergem & "," & rr.Value
End If
k = 2
Next
End Function
OR
Function spliceUm(r As Range) As String
spliceUm = ""
For Each rr In r
spliceUm = spliceUm & rr.Value & ";"
Next
End Function
答案 4 :(得分:0)
您可以使用以下解决方案在VBA中将范围转换为字符串:
Sub convert()
Dim rng As Range, cell As Range
Dim filter As String
filter = ""
Set rng = Selection
For Each cell In rng
If Not cell Is Nothing Then
filter = """" & cell & """" & "," & filter
End If
Next cell
End Sub
答案 5 :(得分:0)
鉴于明显需要迭代范围,我认为首先将范围复制到数组并通过循环数组来构建字符串要快得多。
答案 6 :(得分:0)
即使在另一个工作表中使用了范围,此操作也可以完成
Function RangeToString(ByVal myRange As range) As String
RangeToString = ""
If Not myRange Is Nothing Then
RangeToString = "=" & myRange.Worksheet.Name & "!" & myRange.Address
End If
End Function
答案 7 :(得分:0)
无需迭代。
Application.Textjoin(Chr(10),TRUE,Range("D3", "D10"))
或
Join(Application.Transpose(Range("D3:D10")),Chr(10))
答案 8 :(得分:-1)
有一种更简单的方法。 假设变量rng是一个范围,那么写:
rng =左(rng,Len(rng))
将奇迹般地变成一个字符串。