Question

我在rails应用程序上创建一个类似于zapier或ifttt的基本ruby。用户创建食谱。我只想显示用户创建的食谱。

我已经使用设备gem进行身份验证。

我的问题：

我是否添加＆＃34;如果是user_signed_in？＆＃34;在每页的顶部？我可以在应用程序布局上添加以上产量吗？有没有更好的办法？

我是否在用户中嵌套食谱？

Answer 1

假设您在用户和食谱之间有很多关联

你可以这样做。使用设计提供的current_user帮助程序并使用current_user来引用您的配方。

因此，在任何有关食谱的页面上，您只需要查询用户创建的食谱。

class RecipesController < ApplicationController
  before_action :set_recipe, only: [:show, :edit, :update, :destroy]

  # GET /recipes
  # GET /recipes.json
  def index
    @recipes = current_user.recipes
  end

  # GET /recipes/1
  # GET /recipes/1.json
  def show
  end

  # GET /recipes/new
  def new
    @recipe = current_user.recipes.build
  end

  # GET /recipes/1/edit
  def edit
  end

  # POST /recipes
  # POST /recipes.json
  def create
    @recipe = current_user.recipes.build(recipe_params)

    respond_to do |format|
      if @recipe.save
        format.html { redirect_to @recipe, notice: 'Recipie was successfully created.' }
        format.json { render :show, status: :created, location: @recipe }
      else
        format.html { render :new }
        format.json { render json: @recipe.errors, status: :unprocessable_entity }
      end
    end
  end

  # PATCH/PUT /recipes/1
  # PATCH/PUT /recipes/1.json
  def update
    respond_to do |format|
      if @recipe.update(recipe_params)
        format.html { redirect_to @recipe, notice: 'Recipie was successfully updated.' }
        format.json { render :show, status: :ok, location: @recipe }
      else
        format.html { render :edit }
        format.json { render json: @recipe.errors, status: :unprocessable_entity }
      end
    end
  end

  # DELETE /recipes/1
  # DELETE /recipes/1.json
  def destroy
    @recipe.destroy
    respond_to do |format|
      format.html { redirect_to recipes_url, notice: 'Recipie was successfully destroyed.' }
      format.json { head :no_content }
    end
  end

  private
    # Use callbacks to share common setup or constraints between actions.
    def set_recipe
      @recipe = current_user.recipes.find(params[:id])
    end

    # Never trust parameters from the scary internet, only allow the white list through.
    def recipe_params
      params.fetch(:recipe, {...})
    end
end

Ruby on rails - 设计 - 仅显示用户创建的内容

1 个答案: