Question

ItemName    Price   CreatedDateTime  
New Card    50.00   2014-05-26 19:17:09.987  
Recharge    110.00  2014-05-26 19:17:12.427  
Promo       90.00   2014-05-27 16:17:12.427  
Membership  70.00   2014-05-27 16:17:12.427  
New Card    50.00   2014-05-26 19:20:09.987

Out Put：需要查询当前小时和的销售额在销毁故障的当时最大限度销售的商品的销售列。

Hour    SaleAmount  BreakDownOfSale  
19      210         Recharge  
16      160         Promo

Answer 1

这应该这样做

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operable program or batch file.

Answer 2

虽然我不清楚这个问题，但根据您所需的输出，您可以使用以下查询。

SELECT DATEPART(HOUR,CreatedDateTime) AS Hour, sum(Price) AS Price, ItemName AS BreakDownOfSale  from TableName WHERE  BY ItemName,DATEPART(HOUR,CreatedDateTime)

将表名和列名替换为实际名称。

希望这有帮助！

Answer 3

以下是示例查询。

您可以使用SQL Server Windows功能来获得所需的结果。

DECLARE @Table TABLE
(
    ItemName NVARCHAR(40),
    Price DECIMAL(10,2),
    CreatedDatetime DATETIME
)

-- Fill table.
INSERT INTO @Table
    ( ItemName, Price, CreatedDatetime )
VALUES           
    ( N'New Card'  ,  50.00 ,  '2014-05-26 19:17:09.987'   ),
    ( N'Recharge'  ,  110.00 , '2014-05-26 19:17:12.427' )  ,
    ( N'Promo'     ,  90.00 ,  '2014-05-27 16:17:12.427' ) , 
    ( N'Membership' , 70.00  , '2014-05-27 16:17:12.427' ) , 
    ( N'New Card'  ,  50.00 ,  '2014-05-26 19:20:09.987' )


-- Check record(s).
SELECT * FROM @Table

-- Get record(s) in required way.
;WITH T1 AS 
(
    SELECT 
        DATEPART(HOUR, T.CreatedDatetime) AS Hour, 
        CONVERT(DATE, T.CreatedDatetime) AS Date,
        T.ItemName AS BreakDownOfSales, 
        -- Date and hour both will give unique record(s)
        SUM(Price) OVER (PARTITION BY CONVERT(DATE, T.CreatedDatetime), DATEPART(HOUR, CreatedDateTime)) AS SaleAmount, 
        ROW_NUMBER() OVER(PARTITION BY CONVERT(DATE, T.CreatedDatetime), DATEPART(HOUR, T.CreatedDatetime) ORDER BY T.Price DESC) AS RN
    FROM 
        @Table T
) 
SELECT 
    T1.Date ,
    T1.Hour ,
    T1.SaleAmount,
    T1.BreakDownOfSales 
FROM 
    T1 
WHERE T1. RN = 1
ORDER BY 
    T1.Hour

Answer 4

Check this simple solution, Please convert it to SQL Server Query.

This will give you perfect result even if you have multiple date data.

SELECT HOUR(CreatedDateTime), SUM(Price), 
    (SELECT itemname FROM t it WHERE HOUR(ot.CreatedDateTime) = HOUR(it.CreatedDateTime) AND 
        DATE(ot.CreatedDateTime) = DATE(it.CreatedDateTime) 
        GROUP BY itemname
        ORDER BY price DESC
        LIMIT 1
    ) g
FROM t ot
GROUP BY HOUR(CreatedDateTime);

任何人都帮助我解决这个问题，我尽我所能，但没有解决这个问题？

4 个答案: