我试图通过使用在数据库中插入一些数据 detailsView插入命令。它不起作用。这是我的代码 背后。我设法成功插入.aspx页面buti有一些限制,因为我还需要使用gridview的行作为数据,我只能在aspx.cs页面中完成它。
protected void DetailsView1_ItemInserting(object sender, DetailsViewInsertEventArgs e)
{
string Price;
string Item;
string PetitionType;
string Note;
string UserNameGV = (GridView1.SelectedRow.Cells[3].Text);
string InvoiceGV = (GridView1.SelectedRow.Cells[5].Text);
string CreatedDateGV = (GridView1.SelectedRow.FindControl("lblLocalTime") as Label).Text;
SearchTB.Text = UserNameGV + " " + InvoiceGV + " " + CreatedDateGV;
DateTime CreatedDate = Convert.ToDateTime(CreatedDateGV);
for (Int32 attempt = 1; ;)
{
using (SqlConnection con = new SqlConnection(System.Configuration.ConfigurationManager.ConnectionStrings["RapidVisaConnectionString"].ConnectionString))
{
try
{
Price = ((TextBox)DetailsView1.Rows[1].FindControl("TextBox2")).Text;
Item = ((DropDownList)DetailsView1.Rows[1].FindControl("DropDownList2")).SelectedValue;
PetitionType = ((DropDownList)DetailsView1.Rows[1].FindControl("DropDownList3")).SelectedValue;
Note = ((TextBox)DetailsView1.Rows[1].FindControl("TextBox2")).Text;
con.Open();
string Sql = "INSERT INTO InvoiceDetail (Price, Item, PetitionType, Note, Paid, Quantity, Invoice, UserName, CreatedDate) VALUES (@Price, @Item, @PetitionType, @Note, @Paid, @Quantity, @Invoice, @UserName, @CreatedDate)";
SqlCommand cmd = new SqlCommand(Sql, con);
cmd.Parameters.AddWithValue("@Price", Price);
cmd.Parameters.AddWithValue("@Item", Item);
cmd.Parameters.AddWithValue("@PetitionType", PetitionType);
cmd.Parameters.AddWithValue("@Note", Note);
cmd.Parameters.AddWithValue("@Paid", 1);
cmd.Parameters.AddWithValue("@Quantity", 1);
cmd.Parameters.AddWithValue("@Invoice", InvoiceGV);
cmd.Parameters.AddWithValue("@UserName", UserNameGV);
cmd.Parameters.AddWithValue("@CreatedDate", CreatedDate);
cmd.ExecuteNonQuery();
return;
}
catch (SqlException sqlException)
{
// Increment Trys
attempt++;
// Find Maximum Trys
// Override the web.config setting of 4 for retrys for this method because we are getting time-out errors.
Int32 maxRetryCount = Int32.Parse(ConfigurationManager.AppSettings["ConnectionRetrys"]);
//Int32 maxRetryCount = 5;
// Throw Error if we have reach the maximum number of retries
if (attempt == maxRetryCount)
{
ErrorLog EL = new ErrorLog();
EL.WriteErrorWithSubjectNoWriteToDB("", "Error InvoiceDetail Max Retry");
//going to stop throwing an error because we are getting too many
//throw;
break;
}
// Determine if we should retry or abort.
if (!SQLUtilities.RetryLitmus(sqlException))
{
ErrorLog EL = new ErrorLog();
EL.WriteErrorWithSubjectNoWriteToDB("Insert Failed RetryLitmus for user " + UserName + ". Sql exception number " + sqlException.Number.ToString() + ". " + sqlException.ToString(), "Error InvoiceDetail Failed Litmus");
//going to stop throwing an error because we are getting too many
//throw;
break;
}
else
Thread.Sleep(SQLUtilities.ConnectionRetryWaitSeconds(4));
//Changed from default of 5 seconds to 3 seconds
//Thread.Sleep(SQLUtilities.ConnectionRetryWaitSeconds(attempt));
}
}
}
}
以下是我收到的错误消息。
数据源不支持插入' DetailsViewDS'除非 指定了InsertCommand。问题是我不想在aspx页面中添加InsertCommand,仅在aspx.cs中添加
答案 0 :(得分:0)
我已经测试了你的代码,做了一些修改并且它有效。我已经使用了我的数据库表,你可以根据需要修改它。修改DetailsView1_ItemInserting中的SqlDataSource和C#代码,如下所述。它会很完美。
的SqlDataSource:
<asp:SqlDataSource ID="SqlDataSource1" runat="server" ConnectionString="<%$ ConnectionStrings:ConnectionString %>"
SelectCommand="SELECT * FROM [Image]" InsertCommand="INSERT INTO [Image] ([Name]) VALUES (@Name)">
<InsertParameters>
<asp:Parameter Name="Name" Type="String" />
</InsertParameters>
</asp:SqlDataSource>
从代码中插入
protected void DetailsView1_ItemInserting(object sender, DetailsViewInsertEventArgs e)
{
SqlDataSource sqldsInsertPassword = new SqlDataSource();
sqldsInsertPassword.ConnectionString = ConfigurationManager.ConnectionStrings["ConnectionString"].ConnectionString;
sqldsInsertPassword.ProviderName = ConfigurationManager.ConnectionStrings["ConnectionString"].ProviderName;
sqldsInsertPassword.InsertCommand = "INSERT INTO Image (Name) VALUES (@Name)";
sqldsInsertPassword.InsertCommandType = SqlDataSourceCommandType.Text;
sqldsInsertPassword.InsertParameters.Add("Name", e.Values[0].ToString());
sqldsInsertPassword.Insert();
}
我希望它能解决你的问题。 此致!