Question

我的数据库中有如下名称......

使用下面的代码，我在页面上看到这些用户，旁边有一个复选框。

 $select_from_user_table = "SELECT  contacts.contact_id, user.username
FROM contacts 
INNER JOIN user
ON contacts.contact_id=user.user_id WHERE contacts.user_id = '$user_id'";

    //get the result of the above
    $result2=mysqli_query($con,$select_from_user_table); 
    //show the usernames, phone numbers
    while($row = mysqli_fetch_assoc($result2)) {
    echo "<input type='checkbox' name='check_contacts[]' >" . $row['username'] . "<br>";


if(!empty($_POST['check_contacts'])) {
    foreach($_POST['check_contacts'] as $check) {
            echo $check; //echoes the value set in the HTML form for each checked checkbox.
                         //so, if I were to check 1, 3, and 5 it would echo value 1, value 3, value 5.
                         //in your case, it would echo whatever $row['Report ID'] is equivalent to.
    }
}
    }
    $con->close();

如果选中复选框，我怎么能这样做？如果检查了这些名字，结果将像Will Shakespeare John Grisham一样回显？我想在input type部分我会简单地提出

value=" $row['username'] "

但它不起作用。

Answer 1

您希望将表单回显如下：

echo "<label><input type='checkbox' name='check_contacts[]' value='". $row['contact_id'] ."'>". $row['username'] ."</label>";

验证时我建议先isset()使用!empty()：

if(isset($_POST['check_contacts']) && !empty($_POST['check_contacts'])){
  foreach($_POST['check_contacts'] as $value){
    echo $value;
  }
}

如果索引不存在，则不会以这种方式提示警告。

如果在提交表单时没有选中复选框，则数组将为空并且不显示任何值。

最好将id用作值，因为您始终可以使用它们查询数据库。

Answer 2

此代码适用于我：

 //this code below will get the username of contacts
 // for $user_id 
 $select_from_user_table = "SELECT  contacts.contact_id, user.username
FROM contacts 
INNER JOIN user
ON contacts.contact_id=user.user_id WHERE contacts.user_id = '$user_id'";

    //get the result of the above
    $result2=mysqli_query($con,$select_from_user_table); 
    ?>

        <form action="" method="post">
    <?php
    //show the usernames, phone numbers
    while($row = mysqli_fetch_assoc($result2)) { ?>
     <input type='checkbox' name='check_contacts[]' value='<?=$row['username']?>'> <?php echo $row['contact_id'] ?> </br>

        <?php   
        //we need the php bracket below to close the while loop
}

            ?>
        <input type="submit" />
    </form>

<?php

if(!empty($_POST['check_contacts'])) {
    foreach($_POST['check_contacts'] as $check) {
            echo $check; //echoes the value set in the HTML form for each checked checkbox.
                         //so, if I were to check 1, 3, and 5 it would echo value 1, value 3, value 5.
                         //in your case, it would echo whatever $row['Report ID'] is equivalent to.
    }
}

    $con->close();

    ?>

如何回显我选中的复选框？

2 个答案: