Question

我有一个稀疏矩阵随机矩阵，如下所示：

import numpy as np
from scipy.sparse import rand
foo = rand(100, 100, density=0.1, format='csr')

我想迭代特定行中的单元格并执行两次计算：

row1 = foo.getrow(bar1)
row2 = foo.getrow(bar2)

"""
Like the following:
sum1 = 0
sum2 = 0
for each cell x in row1:
    sum1 += x
    if the corresponding cell (in the same column) in row2 y is non-zero:
        sum2 += x*y
"""

Answer 1

这是一种方法 -

# Get first row summation by simply using sum method of sparse matrix
sum1 = row1.sum()

# Get the non-zero indices of first row
idx1 = row1.indices
data1 = row1.data  # Or get sum1 here with : `data1.sum()`.

# Get the non-zero indices of second row and corresponding data
idx2 = row2.indices
data2 = row2.data

# Get mask of overlap from row1 nonzeros on row2 nonzeros. 
# Select those from data2 and sum those up for the second summation o/p.
sum2 = data1[np.in1d(idx1,idx2)].dot(data2[np.in1d(idx2,idx1)])

或者，正如comments by @user2357112中所建议的那样，我们可以简单地使用matrix-multiplication来获得第二次求和 -

sum2 = sum((row1*row2.T).data)

如何迭代SciPy稀疏矩阵中的一行？

1 个答案: