excel - 从一对多工作表创建多对一工作表

时间:2017-01-19 17:03:16

标签: excel vba excel-vba

我在Excel中有一张表,类似于:

| Value1 | Data1 | Data1b | 1,3,4,8 |
| Value2 | Data2 | Data2b | 2       |
| Value3 | Data3 | Data3b | 6,7,8   |

我想把那个工作表再制作另一个工作表,将最后一列分成不同的行并保持其他数据同步。因此,当第一张纸更新时,第二张纸也会更新。如果在第一张工作表中的最后一列添加了一个数字,则会在第二张工作表中添加一个新行。

第二张表应如下所示:

| Value1 | Data1 | Data1b | 1 |
| Value2 | Data2 | Data2b | 2 |
| Value1 | Data1 | Data1b | 3 |
| Value1 | Data1 | Data1b | 4 |
| Value3 | Data3 | Data3b | 6 |
| Value3 | Data3 | Data3b | 7 |
| Value1 | Data1 | Data1b | 8 |
| Value3 | Data3 | Data3b | 8 |

更新:以下是我尝试使用的代码。首先,我有最好的方法吗?然后清理然后重新填充正确的方法来更新第二张表格?最后,如何更新第一张表格时如何自动运行?

更新:唯一仍然不起作用的是最后的排序,是否有人知道为什么?

Private FROM_SHEET As String
Private TO_SHEET As String
Private START_ROW As Long
Private NUM_COL As Long

Sub oneToMany()

    FROM_SHEET = "Sheet1"
    TO_SHEET = "Sheet2"
    START_ROW = 2
    NUM_COL = 4

    Dim fromSheet As Worksheet
    Dim toSheet As Worksheet
    Dim newRow As Long

    Set fromSheet = Sheets(FROM_SHEET)
    Set toSheet = Sheets(TO_SHEET)

    toSheet.UsedRange.ClearContents

    newRow = START_ROW
    For i = START_ROW To fromSheet.Cells(fromSheet.Rows.Count, 1).End(xlUp).Row
        Dim col As String
        Dim nums() As String

        col = fromSheet.Cells(i, NUM_COL)
        nums = Split(col, ",")

        For Each num In nums
            fromSheet.Rows(i).Copy toSheet.Rows(newRow)
            toSheet.Cells(newRow, NUM_COL) = Trim(num) 'Should copy then overwrite?
            newRow = newRow + 1
        Next num
    Next

    'Sort not working
    toSheet.Range(toSheet.Cells(START_ROW, START_COL), toSheet.Cells(lastRow, lastCol)).Sort _
        key1:=toSheet.Range(toSheet.Cells(START_ROW, NUM_COL), toSheet.Cells(lastRow, NUM_COL)), _
        order1:=xlAscending, Header:=xlNo

End Sub

1 个答案:

答案 0 :(得分:1)

在回答您的第一个问题时,如果这是表单上的唯一数据,那么您的clearcontents方法就可以了。

要自动运行,请查看Sheet1上的Worksheet_Change事件。您可以根据更改的单元格来定位更改....

Private Sub Worksheet_Change(ByVal Target As Range)

If Target.Row < 4 And Target.Column < 5 Then
    Call oneToMany
End If

End Sub