Question

我在表格中有jsonb字段，其值如下：

{
"1":[{"start":64800,"finish":68400},{"start":61200,"finish":64800},{"start":75600,"finish":79200},{"start":79200,"finish":82800}],
"2":[{"start":68400,"finish":72000},{"start":72000,"finish":75600},{"start":75600,"finish":79200},{"start":79200,"finish":82800}],
"3":[{"start":46800,"finish":50400},{"start":50400,"finish":54000}],
"4":[{"start":50400,"finish":54000}],
"5":[{"start":79200,"finish":82800},{"start":82800,"finish":0},{"start":0,"finish":3600}],
"6":[{"start":68400,"finish":72000},{"start":72000,"finish":75600},{"start":79200,"finish":82800}]
}

0 ... 6 - 星期几，这是一系列的工作时间。

所以我需要按周计算工作时间。例如，一行有

"5":[{"start":79200,"finish":82800},{"start":82800,"finish":0},{"start":0,"finish":3600}]

另一行有

"5":[{"start":75600,"finish":79200}]

我希望得到

"5":[{"start":75600,"finish":79200},{"start":79200,"finish":82800},{"start":82800,"finish":0},{"start":0,"finish":3600}]

Answer 1

如果您需要手动运行此报告，请执行以下操作：不规则地，你可以自己做within PostgreSQL。但是如果性能对您很重要，那么您应该规范化您的模式（例如，如果您的jsonb列的结构很简单，那么根本就没有必要使用JSON：您没有任何非结构化数据）

SELECT jsonb_object_agg(dow, working_times_agg)
FROM   (SELECT     dow, jsonb_agg(working_time) working_times_agg
        FROM       table t,
                   jsonb_each(t.jsonb_column) o(dow, working_times),
                   jsonb_array_elements(working_times) working_time
        GROUP BY   dow) working_times_agg_by_dow

如何聚合jsonb对象？

1 个答案: