如何验证0到59的文本字段，它将允许1,2,3，* / 59

Question

我需要为此测试用例验证Textbox。

1. 除*，/
外，不允许0到59个字符和特殊字符
2. 它将允许1,2,3,4但1,2,3,60不允许
3. 允许 / 59或1,2,3,4， / 59但1,2,3,5，* / 59/19不允许

我试过了，

var input = document.getElementById('configMinute').value;      

            //console.info("Else Called");
                var slashPattern = "/"; 
                var specialChars = "<>@!#$%^&*()_+[]{}?:;|'\"\\,./~`-=";
                var getStringCheck = checkSpecialChar(input,specialChars);

                if(getStringCheck==true){   

                // string = 1,2,3,*/10
                // ,*/

                    var getStringValues = input.split(',');     

                    var notAllowedCharPattern = "<>@!#$%^&()_+[]{}?:;|'\"\\.~`-=";

                    var allowedChar = checkSpecialChar(input,notAllowedCharPattern);

                        if(allowedChar==false){ 
                        console.info(getStringValues);

                            getStringValues.forEach(function(element){  
                            //string = 1 2 3 */10
                                var validateSlash = checkSpecialChar(element,slashPattern);     

                                if(element.startsWith("*")==true){
                                    var newInput = element.split('/');  
                                    console.info("newInput: "+ element);
                                    newInput.forEach(function(element) {
                                        console.info("newInput Foreach: "+ element);
                                        if(element=='*' || (element>=0 && element <=59)){   
                                            return true;                    
                                        }
                                        else{
                                            alert("Please enter numbers between 0 to 59 or '*' ==>1");
                                            document.getElementById('configMinute').focus();
                                            return false;

                                        }
                                    });                         

                                }else{
                                    console.info("* Else: "+ element);
                                    if(element=='*' || (element>=0 && element <=59)){   
                                        return true;                    
                                    }else{
                                        alert("Please enter numbers between 0 to 59 or '*' ==>1");
                                        document.getElementById('configMinute').focus();
                                        return false;

                                    }
                                }               

                            }); 
                        }else{
                            alert ("File name has special characters \nAllowed Characters are *,/ ==>3");
                            document.getElementById('configMinute').focus();
                            return false;
                        }           
                }else if(input == '*' || (input>=0 && input <=59)){ 
                    return true;        
                }else{
                    alert("Please enter numbers between 0 to 59 or '*' ==>4");
                    document.getElementById('configMinute').focus();
                    return false;
                }   

提前致谢

Answer 1

你可以试试像

这样的正则表达式

data.frame()

它匹配行的开头（(?:(?:^|,)(?:[1-5]?\d|\*?\/59)\b)+$ ）或^，后跟数字0-59或,，可选地前面有/59。然后这个模式可以重复任意次，直到行结束。

See it here at regex101