Ajax直接转向错误功能?以下是我的代码

时间:2017-01-19 12:58:39

标签: jquery ajax syntax-error

这是我的HTML代码  当模糊事件触发时它显示错误,页面也在那里,并且它直接转到错误块并发出警告错误消息

  

这是HTML代码

DatePicker
  

这是我的jquery代码

<form id="myform" name="myform">
    <input type = "text" name = "datepicker"  id="datepicker" />
    <input type="button" id="submitMe">

$(function() {
    $("#datepicker").datepicker({
        dateFormat: "mm-dd-yy",
    }).datepicker("setDate", new Date());
});

$q_customer = $conn->query("SELECT * from orders inner JOIN 
            customer_order on customer_order.order_no 
            =orders.order_no inner join driver_order  on 
            driver_order.order_no=orders.order_no LEFT JOIN 
            customer on customer.phone=customer_order.phone 
            order by k_time" ) or die(mysqli_error());

$k_time = '';

while($f_customer = $q_customer->fetch_array()){?>

  <tr>
    <?php

    if($k_time == '' || $k_time != $f_customer['k_time']){

      $k_time = $f_customer['k_time'];

      echo "<td>".$f_customer['k_time']."</td>";

    } else{
      echo "<td>&nbsp;</td>";
    }
    ?>

    <td><?php echo $f_customer['order_no']?></td>
    <td><?php echo $f_customer['first_name']?></td>
    <td><?php echo $f_customer['last_name']?></td>
    <td><?php echo $f_customer['address']?></td>
    <td><?php echo $f_customer['driver_no']?></td>
    <td><?php echo $f_customer['d_time']?></td>
    <td><?php echo $f_customer['no_ofppl']?></td>

1 个答案:

答案 0 :(得分:0)

将错误代码修复为:

error: function(err) {
    console.log(err);
}  

看看消息说的是什么。 另外 - 如果我不得不猜测,我会说URL部分已损坏 尝试对URL进行硬编码,看看会发生什么 对于未来 - 在PHP代码中嵌入PHP代码是不好的做法。