Laravel Passport使用自己的API失败

时间:2017-01-19 12:40:53

标签: laravel api vue.js single-page-application laravel-passport

我正在用Vue建立一个SPA。我的前端和后端(Laravel)属于相同的代码库。我想通过Laravel Passport Middleware CreateFreshApiToken 来处理我的API(即我的后端)。我正在通过 web.php 在我的 AuthController 中接近我的登录方法。

我的问题: 一旦我通过我的登录方法成功登录,我希望此时Passport创建了 laravel_token cookie 。不是这种情况。 cookie是在页面刷新后创建的。但正如我所说,我正在建立一个SPA,这就是为什么我不想让页面刷新。

我想要的是什么: 我想通过登录方法登录,然后使用Passport CreateFreshApiToken 中间件。之后我想使用(刚刚在中间件中创建) laravel_token cookie ,这样我就可以在SPA的登录部分正确安全地与我自己的API通信。

更多信息:

Kernel.php

// Code...
protected $middlewareGroups = [
    'web' => [
        // other middlewares...
        \Laravel\Passport\Http\Middleware\CreateFreshApiToken::class,
    ],
];
// Code...

AuthController.php

// Code...
public function login()
{
    if (Auth::attempt(['email' => Input::get('email'), 'password' => Input::get('password')], true)) {

        return response()->json([
            'user' => Auth::user(),
            'authenticated' => auth()->check(),
        ]);
    }

    return response()->json(['authenticated' => false], 401);
}
// Code...

Login.vue

// Code...
methods: {
    login: function (event) {

        event.preventDefault();

        this.$http.post(BASE_URL + '/login', {
            email: this.email,
            password: this.password,
        })

        .then(function (response) {

            localStorage.user_id = response.body.user.id;

            router.push({
                name: 'home'
            });
        });
    },
},
// Code...

出了什么问题?这样:

CreateFreshApiToken.php

// Code...
public function handle($request, Closure $next, $guard = null)
{
    $this->guard = $guard;

    $response = $next($request);

    // I'm signed in at this point

    if ($this->shouldReceiveFreshToken($request, $response)) { // returns false unless you refresh the page. That's why it won't create the laravel_token cookie
        $response->withCookie($this->cookieFactory->make(
            $request->user($this->guard)->getKey(), $request->session()->token()
        ));
    }

    return $response;
}

protected function shouldReceiveFreshToken($request, $response)
{
    // both methods below return false
    return $this->requestShouldReceiveFreshToken($request) &&
           $this->responseShouldReceiveFreshToken($response);
}

protected function requestShouldReceiveFreshToken($request)
{
    // $request->isMethod('GET') - returns false because it's a POST request
    // $request->user($this->guard) - returns true as expected
    return $request->isMethod('GET') && $request->user($this->guard);
}

protected function responseShouldReceiveFreshToken($response)
{
    // $response instanceof Response - returns false
    // ! $this->alreadyContainsToken($response) - returns false as expected
    return $response instanceof Response &&
                ! $this->alreadyContainsToken($response);
}
// Code...

我认为我想要实现的目标是正确的吗?如果是,怎么样?

2 个答案:

答案 0 :(得分:0)

我有同样的问题,决定坚持使用client_secret方式。我想这对你现在没有意义,但是我找到了两种方法来接收laravel令牌而不刷新:

1)使用axios或$ http发送虚拟get请求,无论你使用什么 - 令牌都会附加到响应中;

2)在CreateFreshApiToken.php中更改requestShouldReceiveFreshToken方法 - 将return $request->isMethod('GET') && $request->user($this->guard);替换为return ($request->isMethod('GET') || $request->isMethod('POST')) && $request->user($this->guard);

答案 1 :(得分:0)

function consumeOwnApi($uri, $method = 'GET', $parameters = array())
{
    $req = \Illuminate\Http\Request::create($uri, $method, $parameters, $_COOKIE);
    $req->headers->set('X-CSRF-TOKEN', app('request')->session()->token());
    return app()->handle($req)->getData();
}