我编写了一个使用nltk的FreqDist模块的脚本，然后将其转换为pandas数据帧。代码段如下：
.......
import unicodedata
str2 = unicodedata.normalize('NFKD', str1).encode('ascii','ignore')
words = nltk.tokenize.word_tokenize(str2)
fdist = nltk.FreqDist(words)
df = pd.DataFrame.from_dict(fdist, orient='index').reset_index()
df = df.rename(columns={'index':'query_word', 0:'count'})
df2 = df.sort_values(['count'], ascending=[False])
现在，我正在尝试使用plotly绘制它，我的代码片段如下所示：
import plotly.plotly as py
import plotly.graph_objs as go
data = [go.Bar(x= df.query_word, y= df.count)]
py.iplot(data, filename='basic-bar')
当我运行这部分时，我收到以下错误：
---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-15-87d0c9af254b> in <module>()
----> 1 py.iplot(data, filename='basic-bar')
/usr/local/lib/python2.7/dist-packages/plotly/plotly/plotly.pyc in iplot(figure_or_data, **plot_options)
150 if 'auto_open' not in plot_options:
151 plot_options['auto_open'] = False
--> 152 url = plot(figure_or_data, **plot_options)
153
154 if isinstance(figure_or_data, dict):
/usr/local/lib/python2.7/dist-packages/plotly/plotly/plotly.pyc in plot(figure_or_data, validate, **plot_options)
239
240 plot_options = _plot_option_logic(plot_options)
--> 241 res = _send_to_plotly(figure, **plot_options)
242
243 if res['error'] == '':
/usr/local/lib/python2.7/dist-packages/plotly/plotly/plotly.pyc in _send_to_plotly(figure, **plot_options)
1407 fig = tools._replace_newline(figure) # does not mutate figure
1408 data = json.dumps(fig['data'] if 'data' in fig else [],
-> 1409 cls=utils.PlotlyJSONEncoder)
1410 credentials = get_credentials()
1411 validate_credentials(credentials)
/usr/lib/python2.7/json/__init__.pyc in dumps(obj, skipkeys, ensure_ascii, check_circular, allow_nan, cls, indent, separators, encoding, default, sort_keys, **kw)
249 check_circular=check_circular, allow_nan=allow_nan, indent=indent,
250 separators=separators, encoding=encoding, default=default,
--> 251 sort_keys=sort_keys, **kw).encode(obj)
252
253
/usr/local/lib/python2.7/dist-packages/plotly/utils.pyc in encode(self, o)
144
145 # this will raise errors in a normal-expected way
--> 146 encoded_o = super(PlotlyJSONEncoder, self).encode(o)
147
148 # now:
/usr/lib/python2.7/json/encoder.pyc in encode(self, o)
205 # exceptions aren't as detailed. The list call should be roughly
206 # equivalent to the PySequence_Fast that ''.join() would do.
--> 207 chunks = self.iterencode(o, _one_shot=True)
208 if not isinstance(chunks, (list, tuple)):
209 chunks = list(chunks)
/usr/lib/python2.7/json/encoder.pyc in iterencode(self, o, _one_shot)
268 self.key_separator, self.item_separator, self.sort_keys,
269 self.skipkeys, _one_shot)
--> 270 return _iterencode(o, 0)
271
272 def _make_iterencode(markers, _default, _encoder, _indent, _floatstr,
/usr/local/lib/python2.7/dist-packages/plotly/utils.pyc in default(self, obj)
211 except NotEncodable:
212 pass
--> 213 return json.JSONEncoder.default(self, obj)
214
215 @staticmethod
/usr/lib/python2.7/json/encoder.pyc in default(self, o)
182
183 """
--> 184 raise TypeError(repr(o) + " is not JSON serializable")
185
186 def encode(self, o):
TypeError: <bound method DataFrame.count of query_word count
0 1,2 1
1 four 1
2 prefix 1
.. ...... ..
.. ...... ..
3 francesco 1
据我所知，其他SF问题的主题是“不是json serializable ”，而且从错误信息来看，这是编码的问题吗？而不是数据类型。
因为，当我print type(df2.query_word)时，<class 'pandas.core.series.Series'>。那么如何制作一系列可序列化？由于回溯未显示任何编码错误，例如here或here。
简单的转身是什么？发表这个问题的主要内容是要了解这是数据框架，数据，ipython还是情节问题。