我不知道如何调整数据表中的复选框。我想条件是如果数据表中的复选框被检查,我将它插入我的数据库,如果取消选中,我将删除它在数据库中。我正在使用codeigniter框架。
这是我的控制器:
public function getalldocs() {
$listdocs = $this->Admin_model->getdoctors();
$data = array();
foreach ($listdocs as $docs) {
$row = array();
$row[] = $docs->user_fname;
$row[] = $docs->user_mname;
$row[] = $docs->user_lname;
$row[] = '<input name="user_id[]" value="'.$docs->user_id.'" type="checkbox">';
$data[] = $row;
}
$output = array(
"data" => $data,
);
echo json_encode($output);
}
这是我的javascript,我设法在我点击复选框时提醒user_id的值,但我不知道如何调整它,检查或检查并再次取消选中。这是:
function show_docs() {
$("#dataTables-docs").dataTable().fnDestroy();
table = $('#dataTables-docs').DataTable({
"ajax": {
"url": "<?php echo site_url('admin_controls/getalldocs')?>",
"type": "POST",
},
responsive: true,
className: 'select-checkbox',
'bInfo': false,
'paging': false
});
}
$('#dataTables-docs tbody').on('click', 'input[type="checkbox"]', function(e){
var user_id = $(this).val();
alert(user_id);
});
以下是我的观点:
<table id="dataTables-docs" class="table table-striped table-bordered table-hover dataTable dtr-inline" role="grid" style="width: 100%;" width="100%" aria-describedby="dataTables-material">
<thead>
<tr>
<th>First Name</th>
<th>Middle Name</th>
<th>Last Name</th>
<th></th>
</tr>
</thead>
<tbody>
</tbody>
</table>
答案 0 :(得分:0)
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<body>
<table id="dataTables-docs" class="table table-striped table-bordered table-hover dataTable dtr-inline" role="grid" style="width: 100%;" width="100%" aria-describedby="dataTables-material">
<thead>
<tr>
<th>First Name</th>
<th>Middle Name</th>
<th>Last Name</th>
<th><input type="checkbox" value="sdsd">Check</th>
</tr>
<tr>
<th>First Name</th>
<th>Middle Name</th>
<th>Last Name</th>
<th><input type="checkbox" value="sdsd">Check</th>
</tr>
<tr>
<th>First Name</th>
<th>Middle Name</th>
<th>Last Name</th>
<th><input type="checkbox" value="sdsd">Check</th>
</tr>
</thead>
<tbody>
</tbody>
</table>
<script>
$(document).on('change', 'input[type="checkbox"]', function(e){
if($(this).is(":checked"))
{
alert("Checkbox Is Checked");
}
else
{
alert("Checkbox Is Not Checked");
}
});
</script>
</body>
</html>
&#13;
在jquery中检查是(&#34;:已检查&#34;)
$(document).on('change', 'input[type="checkbox"]', function(e){
if($(this).is(":checked"))
{
alert("Checkbox Is Checked");
}
else
{
alert("Checkbox Is Not Checked");
}
});
答案 1 :(得分:0)
$('#dataTables-docs tbody').on('click', 'input[type="checkbox"]', function(e){
for(i = 0; i < $("input[type="checkbox"]").length; i++){
if($(this).porp("checked")){
//delete function
}
}
})