Question

我在执行以下代码时收到此错误消息。

列名或提供的值与表定义不匹配。

       --DROP TABLE #UniqueBuildingUsageFkAndBuildingFk
         CREATE TABLE #UniqueUsageFkAndBuildingFk (
         Building_fk INT NOT NULL 
         ,Usage_fk INT NOT NULL DEFAULT(0)
         );

         ;WITH UnknownUsageFkAndBuildingFkCTE AS (
        SELECT DISTINCT mm.Building_fk, 0 AS Usage_fk FROM Customers.StandardizedRecord sr
        JOIN Customers.MidasMatch mm ON mm.CustomersBuildingNumberKey = sr.CustomersBuildingNumberKey
        WHERE sr.CustomersBuildingNumberKey NOT IN (SELECT DISTINCT emm.CustomersBuildingNumberKey FROM
        [Customers].[CustomersBuildingNumberKeyCustomersUsageXRef] ebu 
        JOIN [Customers].[MidasMatch] emm ON emm.CustomersBuildingNumberKey = ebu.CustomersBuildingNumberKey WHERE emm.Building_fk > 0)
        AND mm.Building_fk > 0 
        ) 
        INSERT INTO #UniqueUsageFkAndBuildingFk 
        SELECT Building_fk, Usage_fk
        FROM UnknownUsageFkAndBuildingFkCTE;

但是当我注释掉INSERT INTO #UniqueUsageFkAndBuildingFk行时，我会返回所需的结果集。

我迷失了......

Answer 1

在您的表Building_fk, Usage_fk, CustomersBuildingNumberKey中，您有3列（INSERT INTO #UniqueUsageFkAndBuildingFk SELECT Building_fk, Usage_fk, 0 FROM UnknownUsageFkAndBuildingFkCTE;）。因此，在插入此表时，您必须为这三列

指定值

INSERT INTO #UniqueUsageFkAndBuildingFk (Building_fk, Usage_fk)
SELECT Building_fk, Usage_fk
FROM UnknownUsageFkAndBuildingFkCTE;

或者您可以在插入中指定列

{{1}}

Answer 2

正如Abdul在上面的回答，我意识到我错过了（Building_fk，Usage_fk）行INSERT INTO #UniqueUsageFkAndBuildingFk

INSERT INTO SELECT给出：列名或提供的值数与表定义不匹配

2 个答案: