Question

所以我有这个ChoiceType Form将对项目进行排序：

$sort = $this->createForm(ChoiceType::class, NULL, array(
    'choices' => array(
        '...' => 'default',
        'A-Z' => 'title_up',
        'Z-A' => 'title_down',
        'Price low to high' => 'price_up',
        'Price high to low' => 'price_down',
    ),
));

我想使用Choices，以便从下拉菜单中选择其中一个时执行此操作：$products = "SELECT a FROM AppBundle:Product a ORDER BY a.title ASC"。

我试过了：

$sort->handleRequest($request);
if($sort->isSubmitted() && $sort->isValid()) {
    if (isset($default)) {
        $products = "SELECT a FROM AppBundle:Product a ORDER BY a.title ASC";
        return $this->render('AppBundle:main:index.html.twig', array('products' => $products, ));
    }
}

但$default无效，因为未定义。我不知道如何访问choices，因此我可以将它们传递给if语句。

Answer 1

我认为你需要写下这样的东西：

$sort = $this->createFormBuilder()
    ->setAction($this->generateUrl('your_process_route_here'))
    ->setMethod('POST')
    ->add('select', ChoiceType::class, [
        'placeholder' => 'Please select',
        'choices' => [
            '...' => 'default',
            'A-Z' => 'title_up',
            'Z-A' => 'title_down',
            'Price low to high' => 'price_up',
            'Price high to low' => 'price_down',
        ]
    ])

要获取<select>元素中的值：

$select = $request->request->get('select'); // this will contain whatever value you've selected from the dropdown

检查值是否符合预期，然后创建查询：

if ('default' == $select){ // or you can use a switch
    // create a custom method inside your Repository class containing the SELECT, and call it here
}

来自select的{{1}}将是您的->add('select', ...) html元素的名称属性。

处理请求：ChoicesType

1 个答案: