Question

假设我有行表，

Id  Value
----------
1    a
1    b
1    c
1    d
1    e
1    f

，预期结果应为，

Id  Value1   Value2
-------------------
1    a        b
1    c        d
1    e        f

我在这里很困惑。

Answer 1

好的，这绝对是一种更简单的方法，但这样做有效：

WITH CTE AS
(
    SELECT  *,
            RN = ROW_NUMBER() OVER(PARTITION BY Id ORDER BY Value)
    FROM dbo.YourTable
)
SELECT  Id,
        MIN(CASE WHEN RN % 2 = 1 THEN Value END) Value1, 
        MIN(CASE WHEN RN % 2 = 0 THEN Value END) Value2
FROM CTE
GROUP BY Id,
         RN - ((RN - 1) % 2);

结果如下：

╔════╦════════╦════════╗
║ Id ║ Value1 ║ Value2 ║
╠════╬════════╬════════╣
║  1 ║ a      ║ b      ║
║  1 ║ c      ║ d      ║
║  1 ║ e      ║ f      ║
╚════╩════════╩════════╝

Answer 2

;WITH cte AS
(
  SELECT *, ROW_NUMBER() OVER (ORDER BY value) AS RowNum
  FROM YourTable
)

SELECT 
    c1.id
  , c1.value as Value1
  , c2.value as Value2
FROM cte c1
LEFT JOIN cte c2 ON c1.rownum = c2.rownum - 1
WHERE c1.RowNum % 2 = 1

Answer 3

select      Id
           ,min(Value)  as Value1
           ,max(Value)  as Value2

from       (select      Id,Value
                       ,(row_number () over 
                            (partition by Id order by Value)+1)/2 as group_id

            from        mytable as t
            ) t

group by    Id      
           ,group_id

合并第1行和第2行，第3行和第4行，依此类推

3 个答案: