Question

如何从星期六星期六结束的当周开始从sql server获取数据，所以选择本周的星期六到星期五的所有数据。

我找到了这段代码，但是在周日开始，我无法改变它：

where Date >= dateadd(day, 1-datepart(dw, getdate()), CONVERT(date,getdate())) AND Date <  dateadd(day, 8-datepart(dw, getdate()), CONVERT(date,getdate()))

Answer 1

在MS Docs上查看SET DATEFIRST。

将一周的第一天设置为1到7之间的数字。

其中：

1   Monday
2   Tuesday
3   Wednesday
4   Thursday
5   Friday
6   Saturday
7   Sunday (default, U.S. English)

看看下一个例子：

DECLARE @CurrentDate DATETIME;
SET @CurrentDate = CONVERT(DATETIME,'2017-01-18');

SET DATEFIRST 1
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-16' (Monday)

SET DATEFIRST 2
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-17' (Tuesday)

SET DATEFIRST 3
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-18' (Wednesday)

SET DATEFIRST 4
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-12' (Thursday)

SET DATEFIRST 5
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-13' (Friday)

SET DATEFIRST 6
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-14' (Saturday)

SET DATEFIRST 7
SELECT DATEADD(day, 1 - DATEPART(dw, @CurrentDate), @CurrentDate);
RETURNS '2017-01-15' (Monday)

您可以在此处查看：http://rextester.com/YSGVM53271

Answer 2

默认情况下，周将从sunday开始。要更改它，请使用DATEFIRST。

SET DATEFIRST 6

WHERE  Date >= Cast(Dateadd(dd, -Datepart(WEEKDAY, Getdate()) + 1, Getdate()) AS DATE)
       AND Date < Cast(Dateadd(dd, 7 - Datepart(WEEKDAY, Getdate()) + 1, Getdate()) AS DATE)

有关DATEFIRST

的更多信息

+---------------------------+--------------------------+
|           Value           | First day of the week is |
+---------------------------+--------------------------+
| 1                         | Monday                   |
| 2                         | Tuesday                  |
| 3                         | Wednesday                |
| 4                         | Thursday                 |
| 5                         | Friday                   |
| 6                         | Saturday                 |
| 7 (default, U.S. English) | Sunday                   |
+---------------------------+--------------------------+

Answer 3

您可以尝试以下操作。无论SET DATEFIRST值如何，它都能正常工作：

where [Date] >= CAST(DATEADD(d, -(@@DATEFIRST + DATEPART(dw, GETDATE())) % 7, @d) as DATE)
  and [Date] < CAST(DATEADD(d, -(@@DATEFIRST + DATEPART(dw, GETDATE())) % 7 + 6, @d) as DATE)

Answer 4

尝试这个例子

SELECT count(AddTime) AS time,
   CASE
       WHEN (weekday(AddTime)<=3) THEN date(AddTime + INTERVAL (3-weekday(AddTime)) DAY)
       ELSE date(AddTime + INTERVAL (3+7-weekday(AddTime)) DAY)
   END AS week_days
FROM SAAS_Appoint
WHERE Status = 2
AND AddTime > "2020-01-01 00:00:00"
GROUP BY week_days;

$ weekArr = array（'Monday'=> 0，'Tuesday'=> 1，'Wednesday'=> 2，'Thursday'=> 3，'Friday'=> 4，'周六'=> 5， 'Sunday'=> 6）;

示例从星期五开始，到今天结束。只需将3替换为您喜欢的任何一天。

如何获取当前周的数据从星期五的星期六结束从SQL服务器开始

4 个答案: