Question

我有一个如下所述的表结构：

persons
+----+------+
| id | name |
+----+------+
| 1  | Bart |
| 2  | Lisa |
+----+------+

keys
+----+--------+
| id | key    |
+----+--------+
| 1  | gender |
| 2  | age    |
+----+--------+

values
+----+-----------+--------+--------+
| id | person_id | key_id | value  |
+----+-----------+--------+--------+
| 1  | 1         | 1      | male   |
| 2  | 1         | 2      | 10     |
| 3  | 2         | 1      | female |
| 4  | 2         | 2      | 8      |
+----+-----------+--------+--------+

我需要得到一个像这样的表：

+-----------+------+--------+-----+
| person_id | name | gender | age |
+-----------+------+--------+-----+
| 1         | Bart | male   | 10  |
| 2         | Lisa | female | 8   |
+-----------+------+--------+-----+

我可以通过使用LEFT JOIN来实现这一点，但这并不是动态的。

我可以创建一个生成SQL的PHP脚本，但必须有办法让查询动态生效。

Answer 1

Conditional Aggregation + Join

SELECT p.person_id,
       p.NAME,
       Max(CASE WHEN key_id = 1 THEN value END) AS Gender,
       Max(CASE WHEN key_id = 2 THEN value END) AS Age
FROM   VALUES v
       JOIN person p
         ON v.person_id = p.id
GROUP  BY p.person_id,
          p.NAME

摆脱Keys和Values表格，在Age表格本身中添加名为Gender和Person的两列

使用键值对连接MySQL表

1 个答案: