我正在使用jQuery Autocomplete 1.8。每次返回包含输入的每个字符串作为子字符串。如何让它只返回包含输入的字符串作为前缀?
答案 0 :(得分:1)
我在sql中这样做。我正在使用php生成json
<?php
set_include_path(get_include_path() . ':' . '/home/lms/library/php');
set_include_path(get_include_path() . ':' . '/home/lms/systems/ORM');
require_once("Configuration.php");
require_once("DALI_Class.php");
//$unitID = $_POST['unitID'];
$unitID = $_GET["term"];
$return_array=array();
$row_array=array();
$lmsAdminSysDB = DALI::connect(LMS_MIDDLEWARE_DATABASE);
$selectUnit = "SELECT " .
"UnitID, " .
"Title " .
"FROM UnitTBL " .
"WHERE UnitID LIKE '".$unitID."%' " .
"ORDER BY UnitID " .
"";
$resultUnit = $lmsAdminSysDB->Execute($selectUnit);
while($row = $resultUnit->FetchRow()) {
$row_array['label'] = $row['UnitID']." - ".$row['Title'];
$row_array['value'] = $row['UnitID'];
$row_array['title'] = $row['Title'];
array_push($return_array,$row_array);
}
unset($resultUnit);
//header('Content-type: application/json');
//echo json_encode($result);
DALI::disconnect($lmsAdminSysDB);
echo json_encode($return_array);
?>