这是我的代码部分:
<div id="canvasImg" class="img-content position-relative">
<loading></loading>
<canvas id="Canvas" class="position-absolute"></canvas>
</div>
使用的CSS:
.position-relative{
position: relative;
}
.position-absolute{
position: absolute;
}
生成画布图像后,我正在动态创建一些图像。
var createCanvasImgDiv = function (markerDetails) {
var result = "<img src='../../../../../sharedAssets/images/device_marker.png'"
+ "class='position-absolute marker-Img'"
+ "id='" + markerDetails.deviceId + "'"
+ "name='" + markerDetails.externalName + "'"
+ "radius='" + markerDetails.radius + "'"
+ "emailTags='" + markerDetails.emails.join(",") + "'"
+ "/>";
return result;
};
_.map(deviceMarkers, function (tempMarker) {
var imagDiv = createCanvasImgDiv(tempMarker);
$("#canvasImg").append(angular.element(imagDiv));
$compile(angular.element(imagDiv))($scope);
});
现在我希望<img>
对象在拖动鼠标时移动到父div(id = canvasImg)内的任何位置。我想要鼠标位置下降时的位置。
请帮我解决这个问题。提前谢谢。
答案 0 :(得分:1)
我已使用jquery-ui draggable widget来实现此目标。
$("#image").draggable({
containment: "parent"
});
$("#image").on("dragstop", function(event, ui) {
alert("mouse position: X:" + event.pageX + ", Y:" + event.pageY);
});
&#13;
.position-relative {
position: relative;
}
.position-absolute {
position: absolute;
}
&#13;
<script src="https://code.jquery.com/jquery-3.1.1.min.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.min.js"></script>
<div id="canvasImg" class="img-content position-relative" style="width:300px;height:200px;border:1px solid #000000;">
<loading></loading>
<canvas id="Canvas" class="position-absolute" style="width:200px;height:100px;border:1px solid #000000;"></canvas>
<img id="image" class="position-relative" src="http://wallpaper.sc/en/ipad/wp-content/uploads/2014/10/ipad-2048x2048-thumbnail_00721-256x256.jpg" style="width:25px;height:25px;" />
</div>
&#13;