Question

我有一个带有函数的类，该函数调用变量，并且由于某种原因它在开头设置时显示为空。（顺便说一下，不是完整的代码）（url用作函数变量中的路径）

    public      $domain         =   'http://rbx-js.herokuapp.com';
    protected   $key            =   '';         

    protected function post($url, $data)
    {
    foreach($data as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
    $fields_string = rtrim($fields_string,'&');

    $ch = curl_init();

    curl_setopt($ch,CURLOPT_URL,$this->domain.$url);
    curl_setopt($ch,CURLOPT_POST,count($data));
    curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
    curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);

    $result = curl_exec($ch);
    return $result;
    }

它将返回如下内容： http:///getPlayers/retrieve/3e75c964ae

Answer 1

在cosntruct中初始化变量：

public      $domain;
protected   $key;     

protected function __construct()
{
    $this->domain = 'http://rbx-js.herokuapp.com';
    $this->key    = '';
}

protected function post($url, $data)
{
    foreach($data as $key=>$value) { $fields_string .= $key.'='.$value.'&'; }
    $fields_string = rtrim($fields_string,'&');

    $ch = curl_init();

    curl_setopt($ch,CURLOPT_URL,$this->domain.$url);
    curl_setopt($ch,CURLOPT_POST,count($data));
    curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string);
    curl_setopt($ch,CURLOPT_RETURNTRANSFER, true);

    $result = curl_exec($ch);
    return $result;
}

PHP变量被读为空

1 个答案: