我有一个ListView，它包含2个textBlocks作为listview Item
我想动态地为textBlocks着色
我该如何处理文本块？ 将会有一个例子。
感谢您的支持
附加我的XAML：
<ListView x:Name="LV" ItemsSource= "{Binding Lggv}" SelectionChanged="dataGridData_SelectionChanged" ItemContainerStyle="{StaticResource ListViewItemStyle}" >
<ListView.ItemTemplate>
<DataTemplate>
<StackPanel >
<Border BorderThickness="1" BorderBrush="Black">
<Grid>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="150"></ColumnDefinition>
<ColumnDefinition Width="50"></ColumnDefinition>
<ColumnDefinition Width="1*"></ColumnDefinition>
</Grid.ColumnDefinitions>
<TextBlock x:Name="tbHeader" Text="{Binding Info }" AllowDrop="True" FontWeight="Bold" Grid.Column="2" >
<TextBlock.Background>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FFCEE6C6" Offset="0.008"/>
<GradientStop Color="#FF9ECF8C" Offset="0.987"/>
</LinearGradientBrush>
</TextBlock.Background>
</TextBlock>
</Grid>
</Border>
<Grid x:Name="GridData" >
<Grid.Background>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FFC5DDFF" Offset="0"/>
<GradientStop Color="#FFA8C8F7" Offset="1"/>
</LinearGradientBrush>
</Grid.Background>
<Grid.ColumnDefinitions>
<ColumnDefinition Width="150"></ColumnDefinition>
<ColumnDefinition Width="50"></ColumnDefinition>
<ColumnDefinition Width="1*"></ColumnDefinition>
</Grid.ColumnDefinitions>
<Border Grid.Column="0" BorderThickness="2" BorderBrush="Black">
<TextBlock Text="{Binding DateTime}" ></TextBlock>
</Border>
<Border Grid.Column="1" BorderThickness="2" BorderBrush="Black">
<TextBlock Text="{Binding ComPort}"></TextBlock>
</Border>
<Border Grid.Column="2" BorderThickness="2" BorderBrush="Black">
<TextBlock Text="{Binding Data}" ></TextBlock>
</Border>
</Grid>
</StackPanel>
</DataTemplate>
</ListView.ItemTemplate>
</ListView>
答案 0 :(得分：1)
执行此操作的最佳方法是使用IValueConverter
因为这可以让你保持你的视图和viewModel分开，不过如果你不关心@sasanaf答案是完全正确的
这是一个简单的基于画笔的转换器
的示例public class PriorityConverter : IValueConverter
{
public Brush HighBrush { get; set; }
public Brush LowBrush { get; set; }
public Brush MediumBrush { get; set; }
public Brush DefaultBrush { get; set; }
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
var priority = value as Priority?;
if (priority.HasValue)
{
switch (priority.Value)
{
case Priority.High:
return HighBrush;
case Priority.Medium:
return MediumBrush;
case Priority.Low:
return LowBrush;
default:
return DefaultBrush;
}
}
else
throw new InvalidCastException($"{value} is not a Priority");
}
然后，您可以将转换器作为资源添加到您的应用程序
<local:PriorityConverter x:Key="PriorityConverter" >
<local:PriorityConverter.DefaultBrush>
<SolidColorBrush Color="{DynamicResource {x:Static SystemColors.ControlColorKey}}"/>
</local:PriorityConverter.DefaultBrush>
<local:PriorityConverter.HighBrush>
<LinearGradientBrush>
<GradientStop Color="Red" Offset="0.5"/>
<GradientStop Color="Yellow" />
</LinearGradientBrush>
</local:PriorityConverter.HighBrush>
<local:PriorityConverter.MediumBrush>
<SolidColorBrush Color="Blue"/>
</local:PriorityConverter.MediumBrush>
<local:PriorityConverter.LowBrush>
<SolidColorBrush Color="Green"/>
</local:PriorityConverter.LowBrush>
</local:PriorityConverter>
最后在绑定上使用它
<TextBlock Background="{Binding Priority, Converter={StaticResource PriorityConverter}}" />
答案 1 :(得分：0)
如果您正在使用MVVM方法，我会在ViewModel中设置颜色并将它们绑定到属性。
编辑： 像这样的文本块：
<TextBlock DataContext="ViewModel"
Background="{Binding SpecificColor}">
</TextBlock>
在ViewModel中，您可以在初始化时或在任何特定事件中指定您想要的颜色。 例如：
private Brush m_SpecificColor;
public Brush SpecificColor
{
get { return m_SpecificColor; }
set
{
m_SpecificColor = value;
OnPropertyChanged("SpecificColor");
}
}
private void SetColor()
{
SpecificColor = (Brush)new BrushConverter().ConvertFromString("Green");
}
答案 2 :(得分：0)
我想您希望根据Lggv源集合中对象的某些属性（具有“Info”，“DateTime”，“ComPort”和“Data”属性的类）动态更改颜色。
然后你可以使用一个带有DataTrigger的样式来绑定到这个类的属性，即类型T（同样这是带有“Info”，“DateTime”，“ComPort”的类型和您绑定到的IEnumerable<T>（Lggv）源集合的“数据”属性：
<TextBlock x:Name="tbHeader" Text="{Binding Info}" AllowDrop="True" FontWeight="Bold" Grid.Column="2">
<TextBlock.Style>
<Style TargetType="TextBlock">
<Setter Property="Background">
<Setter.Value>
<!-- this is the default background-->
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FFCEE6C6" Offset="0.008"/>
<GradientStop Color="#FF9ECF8C" Offset="0.987"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
<Style.Triggers>
<!-- This trigger changes the background to green when the "Info" property of your data object returns "Some info..." -->
<DataTrigger Binding="{Binding Info}" Value="Some info...">
<Setter Property="Background">
<Setter.Value>
<SolidColorBrush>Green</SolidColorBrush>
</Setter.Value>
</Setter>
</DataTrigger>
</Style.Triggers>
</Style>
</TextBlock.Style>
</TextBlock>
答案 3 :(得分：0)
您可以使用IValueConverter将属性转换为背景色。以下是一个例子。
else在资源中声明值转换如下。
class BackgroundColorConverter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter, CultureInfo culture)
{
LinearGradientBrush myLinearGradientBrush = new LinearGradientBrush();
if (value != null )
{
string strValue = value.ToString();
myLinearGradientBrush.StartPoint = new System.Windows.Point(0, 0);
myLinearGradientBrush.EndPoint = new System.Windows.Point(1, 1);
switch (strValue)
{
case "Match1":
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.Yellow, 0.0));
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.Red, 0.25));
break;
case "Match2":
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.Blue , 0.0));
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.BlueViolet, 0.25));
break;
default:
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.Green , 0.0));
myLinearGradientBrush.GradientStops.Add(new GradientStop(Colors.GreenYellow, 0.25));
break;
}
}
return myLinearGradientBrush;
}
public object ConvertBack(object value, Type targetType, object parameter, CultureInfo culture)
{
throw new NotImplementedException();
}
}
以下是Xaml的编码器。
<Window.Resources>
<local:BackgroundColorConverter x:Key="BackgroundColorConverter"/>
</Window.Resources>
另一种方法，如果你想使用资源。您可以在Windows或用户控制资源中定义颜色。在此之后，您将不得不使用IMultiValueConverter。将属性和窗口或用户控件传递给MultiValueConverter。您需要使用相对源来获取绑定中的windows或usercontrol。然后，您可以根据匹配条件返回资源。
答案 4 :(得分：0)
我个人用DataTrigger来做这件事：
<Style x:Key="TextBlockStyle" TargetType="TextBlock">
<Setter Property="Background">
<Setter.Value>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="#FFCEE6C6" Offset="0.008"/>
<GradientStop Color="#FF9ECF8C" Offset="0.987"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
<Style.Triggers>
<DataTrigger Binding="{Binding YourProperty}" Value="YourPropertyValue">
<Setter Property="Background">
<Setter.Value>
<LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0">
<GradientStop Color="Red" Offset="0.008"/>
<GradientStop Color="Orange" Offset="0.987"/>
</LinearGradientBrush>
</Setter.Value>
</Setter>
</DataTrigger>
</Style.Triggers>
</Style>
然后你不必定义一个类来做一个相对简单的任务。