Question

我有3个不同的表：

process table:
| projectNo | process | studio |
+-----------+---------+--------+
| 170001    | ANM BLD | APEX   |
| 170001    | ANM BLD | CANVAS |
| 170002    | CGI MOD | APEX   |
| 170003    | CGI MOD | ORBIT  |

proc_leader table:
| projectNo | process | proc_leader|
+-----------+---------+------------+
| 170001    | ANM BLD | John       |
| 170001    | ANM BLD | James      |
| 170002    | CGI MOD | Peter      |
| 170003    | CGI MOD | Kate       |

proc_checker table:
| projectNo | process | proc_checker|
+-----------+---------+------------+
| 170001    | ANM BLD | Aaron      |
| 170001    | ANM BLD | John       |
| 170002    | CGI MOD | Peter      |
| 170003    | CGI MOD | Adel       |

所以我想做的是创建html表，如下所示：

| username | studio APEX | studio CANVAS | studio ORBIT |
+----------+-------------+---------------+--------------+
| Aaron    |       x     |       x       |              |
| Adel     |             |               |       x      |
| John     |       x     |       x       |              |
| James    |       x     |       x       |              |
| Kate     |             |               |       x      |
| Peter    |       x     |               |              |

所以我想将流程表中的工作室分配给用户名。有可能吗？

Answer 1

您可以UNION使用LEFT JOIN表process领导和检查表。

试试这个：

select
  p2.proc_leader,
  case count(case when p1.studio = 'APEX' then 1 end) > 0 then 'x' end,
  case count(case when p1.studio = 'CANVAS' then 1 end) > 0 then 'x' end,
  case count(case when p1.studio = 'ORBIT' then 1 end) > 0 then 'x' end
from process p1
left join (
  select *
  from proc_leader
  union all
  select *
  from proc_checker
) p2 on p1.projectNo = p2.projectNo
and p1.process = p2.process
group by p2.proc_leader;

Answer 2

我认为以下是您想要的：

select proc_leader,
       max(case when studio = 'APEX' then 'x' else '' end) as APEX,
       max(case when studio = 'CANVAS' then 'x' else '' end) as CANVAS,
       max(case when studio = 'ORBIT' then 'x' else '' end) as ORBIT
from ((select l.proc_leader, p.studio
       from proc_leader l join
            process p
            on l.projectNo = p.projectNo
      ) union all
      (select c.proc_leader, p.studio
       from proc_checker c
            process p
            on c.projectNo = p.project_no
      )
     ) pp
group by proc_leader;

Answer 3

SELECT
  u.username,
  max(if (p.studio = 'APEX',   'x', '')) AS APEX,
  max(if (p.studio = 'CANVAS', 'x', '')) AS CANVAS,
  max(if (p.studio = 'ORBIT',  'x', '')) AS ORBIT
FROM (
  SELECT proc_leader  AS username,projectNo FROM proc_leader
  UNION
  SELECT proc_checker AS username,projectNo FROM proc_checker
) AS u
LEFT JOIN process AS p ON p.projectNo = u.projectNo
GROUP BY 1

如何将表中的一个值从另一个值分配给多个

3 个答案: