我卡住使用HttpURLConnection向网络服务器发出PUT http请求。我有一些代码可以使PUT请求正常,我可以简单地包含“期望100-继续请求属性”#39;然而,在标题中尝试我似乎无法使该功能等待“100继续”#39;在发送实际的http有效负载之前从服务器响应。
我得到以下内容(来自Wireshark)
PUT /post/ HTTP/1.1
User-Agent: curl/7.35.0
Accept: */*
Content-Type: application/x-www-form-urlencoded
Expect: 100-continue
Host: somerandomdomain.info
Connection: keep-alive
Content-Length: 17
Some data for you
HTTP/1.1 100 Continue
...rest of web-server response...
我确定我遗漏了一些显而易见的东西,但是在谷歌搜索后我画了一个空白 - 有人可以帮忙吗?
非常感谢,如果是这样:))
下面的Http PUT代码片段:
String url = "http://somerandomdomain.info";
String postJsonData = "Some data for you\n";
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
// Setting basic post request
con.setRequestMethod("PUT");
con.setRequestProperty("User-Agent", "jcurl/7.35.0");
con.setRequestProperty("Accept", "*/*");
con.setRequestProperty("Content-Length", postData.length() + "");
con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
con.setRequestProperty("Expect", "100-continue");
// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(postData);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post Data : " + postData);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String output;
StringBuffer response = new StringBuffer();
while ((output = in.readLine()) != null) {
response.append(output);
}
in.close();
//printing result from response
System.out.println(response.toString());
答案 0 :(得分:1)
对我来说,为什么他们以这种方式设计它并不明显,但实现Expect:100逻辑的代码仅在您调用setFixedLengthStreamingMode(int contentlen)
或the overload for long
或{{3}之一时使用在做getOutputStream
之前。在这种情况下,我建议第一个最简单。