Question

我需要运行属于对象的所有实例的方法。例如，如果我有方法fullName（），它连接.firstName和.secondName，我想为代码中的对象的两个实例执行此操作：

<script>
    function x(firstName, secondName) {
        this.firstName = firstName;
        this.secondName = secondName;
        this.fullName = function() {
            console.log(this.firstName + this.secondName); //this should output result of both john.fullName() and will.fullName()
        }
    }
    var john = new x("John ", "Smith");
    var will = new x("Will ", "Adams");
</script>

这是如何在javascript中完成的？优选地，它将没有指定实例的数量，而是仅针对已经创建的所有实例运行该方法。提前谢谢。

Answer 1

这是可能的，但请注意，创建的任何x都不会被垃圾回收

最初我有以下代码

var x = (function() {
    var objs = [];
    var x = function x(firstName, secondName) {
        this.firstName = firstName;
        this.secondName = secondName;
        objs.push(this);
        this.fullName = function() {
            objs.forEach(function(obj) {
                console.log(obj.firstName + obj.secondName); //this should output result of both john.fullName() and will.fullName()
            });
        };
    };
})();
var john = new x("John ", "Smith");
var will = new x("Will ", "Adams");
will.fullName();

然而，我想到了它，并认为这更有意义

var x = (function() {
    var objs = [];
    var x = function x(firstName, secondName) {
        this.firstName = firstName;
        this.secondName = secondName;
        objs.push(this);
        this.fullName = function() {
            console.log(this.firstName + this.secondName); //this should output result of both john.fullName() and will.fullName()
        };
    };
    x.fullName = function() {
        objs.forEach(function(obj) {
            obj.fullName();
        });
    }
    return x;
})();
var john = new x("John ", "Smith");
var will = new x("Will ", "Adams");
x.fullName();

如何为对象的所有实例调用方法

1 个答案: