我已根据条件函数实施了分页和过滤:JSBin:
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<link data-require="bootstrap-css@3.x" data-semver="3.1.1" rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" />
<script data-require="angular.js@*" data-semver="1.2.14" src="https://code.angularjs.org/1.2.14/angular.js"></script>
<script src="//cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/0.11.0/ui-bootstrap-tpls.js"></script>
</head>
<body>
<section class="main" ng-controller="contentCtrl">
<div style="float: right; margin-right: 200px">
has more than 3 letters <input type="checkbox" ng-model="criteria.number" ng-true-value="3" ng-false-value="null" /><br>
</div>
<h3>Existing friends</h3>
<div ng-repeat="friend in filteredFriends | filter: criteriaMatch(criteria)">
{{friend.name}}
</div>
<pagination total-items="totalItems" items-per-page="itemsPerPage" ng-model="currentPage"></pagination>
</section>
</body>
</html>
JavaScript的:
var app = angular.module('plunker', ['ui.bootstrap']);
app.factory('friendsFactory', function() {
var o = {
friends: [ {"name":"Jack"}, {"name":"Tim"}, {"name":"Stuart"},
{"name":"Tom"}, {"name":"Frank"}, {"name":"Nicholas"},
{"name":"Jesse"}, {"name":"Amber"}, {"name":"Tom"},
{"name":"Jerry"}, {"name":"Richard"}, {"name":"Mike"},
{"name":"Michael"}, {"name":"Jim"}, {"name":"Louis"}]
};
return o;
});
app.controller('contentCtrl', function ($scope, friendsFactory) {
$scope.friends = friendsFactory.friends;
$scope.totalItems = $scope.friends.length;
$scope.itemsPerPage = 5
$scope.currentPage = 1;
function refresh() {
var begin = (($scope.currentPage - 1) * $scope.itemsPerPage);
var end = begin + $scope.itemsPerPage;
$scope.filteredFriends = friendsFactory.friends.slice(begin, end);
$scope.totalItems = $scope.friends.length;
}
$scope.criteria = { number: "null" };
$scope.criteriaMatch = function (cri) {
return function (friend) {
return ((cri.number === "null") || (friend.name.length > cri.number));
};
};
$scope.$watch('currentPage', refresh);
});
问题在于,选择过滤器后,会显示长度大于3 逐页的名称。我想要的是,它应该重新计算页数,并且每页显示5个好名字。
是否有人知道如何修改程序以实现此目的?
此外,如果我将"null"
替换为null
,则在选择和取消选择过滤器后,它将无效。有谁知道为什么?
PS:它与this thread非常不同;不是重复...
答案 0 :(得分:0)
这是一个解决方案:JSBin:
<!DOCTYPE html>
<html ng-app="plunker">
<head>
<meta name="description" content="filter and pagination 1">
<link data-require="bootstrap-css@3.x" data-semver="3.1.1" rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.1.1/css/bootstrap.min.css" />
<script data-require="angular.js@*" data-semver="1.2.14" src="https://code.angularjs.org/1.2.14/angular.js"></script>
<script src="//cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/0.11.0/ui-bootstrap-tpls.js"></script>
</head>
<body>
<section class="main" ng-controller="contentCtrl">
<div style="float: right; margin-right: 200px">
has more than 3 letters <input type="checkbox" ng-model="criteria.number" ng-true-value="3" ng-false-value="0" /><br>
</div>
<h3>Existing friends</h3>
<div ng-repeat="friend in filteredFriends | start: (currentPage - 1) * itemsPerPage | limitTo: itemsPerPage">
{{friend.name}}
</div>
<pagination total-items="filteredFriends.length" items-per-page="itemsPerPage" ng-model="currentPage"></pagination>
</section>
</body>
</html>
JavaScript的:
var app = angular.module('plunker', ['ui.bootstrap']);
app.factory('friendsFactory', function() {
var o = {
friends: [ {"name":"Jack"}, {"name":"Tim"}, {"name":"Stuart"},
{"name":"Tom"}, {"name":"Frank"}, {"name":"Nicholas"},
{"name":"Jesse"}, {"name":"Amber"}, {"name":"Tom"},
{"name":"Jerry"}, {"name":"Richard"}, {"name":"Mike"},
{"name":"Michael"}, {"name":"Jim"}, {"name":"Louis"}]
};
return o;
});
app.controller('contentCtrl', function ($scope, friendsFactory) {
$scope.friends = friendsFactory.friends;
$scope.criteria = { number: 0 }
$scope.filteredFriends = $scope.friends;
$scope.itemsPerPage = 5
$scope.currentPage = 1;
function refresh() {
$scope.filteredFriends = $scope.friends.filter(function(item){
return item.name.length > $scope.criteria.number;
})
};
$scope.$watch('currentPage', refresh);
$scope.$watch('criteria.number', refresh);
});
app.filter('start', function () {
return function (input, start) {
if (!input || !input.length) { return; }
return input.slice(start);
};
});