我几个小时后就被困在类似的东西上,并制定了一个不那么混乱的代码,用于在单个Teradata查询中输出第25,50,75个百分位数。可以进一步扩展以产生“ 5点摘要”。根据人口估计值得出最小和最大变化静态值。
有人要求优雅的方法。分享我的。
以下是代码:
SELECT MAX(PER_MIN) AS PER_MIN,
MAX(PER_25) AS PER_25,
MAX(PER_50) AS PER_50,
MAX(PER_75) AS PER_75,
MAX(PER_MAX) AS PER_MAX
FROM (SELECT CASE WHEN ROW_NUMBER() OVER(ORDER BY DURATION_MACRO_CURR ASC) = CAST(COUNT(*) OVER() * 0.01 AS INT) THEN DURATION_MACRO_CURR END AS PER_MIN,
CASE WHEN ROW_NUMBER() OVER(ORDER BY DURATION_MACRO_CURR ASC) = CAST(COUNT(*) OVER() * 0.25 AS INT) THEN DURATION_MACRO_CURR END AS PER_25,
CASE WHEN ROW_NUMBER() OVER(ORDER BY DURATION_MACRO_CURR ASC) = CAST(COUNT(*) OVER() * 0.50 AS INT) THEN DURATION_MACRO_CURR END AS PER_50
CASE WHEN ROW_NUMBER() OVER(ORDER BY DURATION_MACRO_CURR ASC) = CAST(COUNT(*) OVER() * 0.75 AS INT) THEN DURATION_MACRO_CURR END AS PER_75
CASE WHEN ROW_NUMBER() OVER(ORDER BY DURATION_MACRO_CURR ASC) = CAST(COUNT(*) OVER() * 0.99 AS INT) THEN DURATION_MACRO_CURR END AS PER_MAX
FROM PROD_EXP_DL_CVM.PROD_CVM
WHERE PW_END_DATE = '2016-10-18'
) BASE
这是所需的输出:
答案 0 :(得分:5)
我会使用条件聚合来做到这一点:
f_name