Question

在现有的python脚本中，我使用vivification来处理字典词典。

class AutoVivification(dict):
        """Implementation of perl's autovivification feature."""

        def __init__(self, *args, **kwargs):
                super(AutoVivification, self).__init__(*args, **kwargs)
                self.vivify = True
                self.root = self

        def __getitem__(self, item):

                try:
                        return dict.__getitem__(self, item)

                except KeyError:
                        if not self.root.vivify:
                                raise
                        value = self[item] = type(self)()
                        value.root = self.root
                        return value

        def unvivify(self):
                self.vivify = False

        def revivify(self):
                self.vivify = True

        def upgrade(self):
                self.root = self

我想在字典词典中为每个字典应用此类。我想到了类似的东西：

def upvivification(dico):
        """Upgrade to the last autovivification version."""

        if isinstance(dico, dict):
                dico = AutoVivification(dico)

                for k in dico:

                        if isinstance(dico[k], dict):
                                upvivification(dico[k])

但是，确实它没有用，因为这个改变的范围在于函数而不是全局...我不知道如何递归地进行这种改变......

Answer 1

最后返回dico并在递归调用中重新分配返回值：

def upvivification(dico):
    if isinstance(dico, dict):
        dico = AutoVivification(dico)
            for k in dico:
                if isinstance(dico[k], dict):
                    dico[k] = upvivification(dico[k])
        return dico

然后使用：

some_dict = upvivification(some_dict)

只能使用优秀pain and care更改现有对象变异样式的type。但是，您可以将旧变量重新分配给新对象。

Answer 2

def upvivification(dico):
        """Upgrade to the last autovivification version."""

        if isinstance(dico, dict):
                dico = AutoVivification(dico)

                for k in dico:

                        if isinstance(dico[k], dict):
                                dico[k] = upvivification(dico[k])
        return deco

并像

一样使用它

new_dico = upvivification(dico)

更改词典词典中每个词典的类型

2 个答案: