Question

我有以下代码从REST数据库中获取所有数据我需要将该List放入javaFX TableView中我见过的所有示例都使用带有tableobject.setItems（ObservableListObject）的ObservableList来填充TableView。我遗漏了一些东西 - 似乎我的通用列表不兼容。任何Sugestions？

编辑：澄清类：是实体类pojo。

public class Customers implements Serializable {

下面的

是FMXLController类

public class CustomerFXMLController {
    @FXML
    private TableView<?> customerTable;
    @FXML
    private TableColumn<?, ?> columnId;
    @FXML
    private TableColumn<?, ?> columnName;
    @FXML
    private TableColumn<?, ?> columnLastName;
    private Customers customer;
    /* single customer class record*/
    private CustomersJerseyClient client;
    private List<Customers> customers;
    @FXML
protected void initialize() {

    client = new CustomersJerseyClient();
    GenericType<List<Customers>> gType = new GenericType<List<Customers>>() {
    };
    Response response = client.findAll_JSON(Response.class);
    customers = response.readEntity(gType);
    customer = customers.get(customersIndex);

Answer 1

假设想法是在表中显示Customers个对象的集合（即表中的每一行包含一个Customers实例），那么你应该相应地声明你的表和列：

@FXML 
private TableView<Customers> customerTable ;

@FXML
private TableColumn<Customers, Number> columnId ;

@FXML
private TableColumn<Customers, String> columnName ;

等（我猜测列的类型，显然）。

然后你就可以了

customerTable.getItems().setAll(customers);

Answer 2

对此的正确解决方案不仅仅是上述答案。因为JavaFX需要使用可观察的东西，所以在具有setter和getter的pojo类CustomerTableModel中处理从String到StringProperty的转换。

@FXML   private TableView<CustomerTableModel> customersTable;
@FXML
private TableColumn<CustomerTableModel, Number> columnId;
@FXML
private TableColumn<CustomerTableModel, String> columnName;
@FXML
private TableColumn<CustomerTableModel, String> columnLastName;
@FXML
private TableColumn<CustomerTableModel, String> columnMobileNumber;

我需要将REST数据放入javaFX TableView中

2 个答案: