Question

看图片：

我希望设计像图像中那样，用户输入4位一次性密码（OTP）。现在我通过4个单独的输入实现了这一点，然后在javascript中组合了值：

<input type="text" class="form-control" placeholder="0" maxlength="1"  />
<input type="text" class="form-control" placeholder="0" maxlength="1" />
<input type="text" class="form-control" placeholder="0" maxlength="1" />
<input type="text" class="form-control" placeholder="0" maxlength="1" />

我不确定这是否正确。我认为必须有一些样式选项，通过这些样式选项，一个输入文本框将像图像中一样显示为分区文本框。是否可以使用bootstrap？如何将一个输入控件设置为输入的分区字段？

Answer 1

你不必保留4个单独的字段;

首先你应该调整字符间距，然后调整底部的边框样式......

＆＃13;

#partitioned {
  padding-left: 15px;
  letter-spacing: 42px;
  border: 0;
  background-image: linear-gradient(to left, black 70%, rgba(255, 255, 255, 0) 0%);
  background-position: bottom;
  background-size: 50px 1px;
  background-repeat: repeat-x;
  background-position-x: 35px;
  width: 220px;
}

＆＃13;

<input id="partitioned" type="text" maxlength="4" />

＆＃13;

- 修改4个字符丑陋的5个下划线 -

＆＃13;

var obj = document.getElementById('partitioned');
obj.addEventListener("keydown", stopCarret); 
obj.addEventListener("keyup", stopCarret); 

function stopCarret() {
	if (obj.value.length > 3){
		setCaretPosition(obj, 3);
	}
}

function setCaretPosition(elem, caretPos) {
    if(elem != null) {
        if(elem.createTextRange) {
            var range = elem.createTextRange();
            range.move('character', caretPos);
            range.select();
        }
        else {
            if(elem.selectionStart) {
                elem.focus();
                elem.setSelectionRange(caretPos, caretPos);
            }
            else
                elem.focus();
        }
    }
}

＆＃13;

#partitioned {
  padding-left: 15px;
  letter-spacing: 42px;
  border: 0;
  background-image: linear-gradient(to left, black 70%, rgba(255, 255, 255, 0) 0%);
  background-position: bottom;
  background-size: 50px 1px;
  background-repeat: repeat-x;
  background-position-x: 35px;
  width: 220px;
  min-width:220px;
}

#divInner{
  left: 0;
  position: sticky;
}

#divOuter{
  width:190px; 
  overflow:hidden
}

＆＃13;

<div id="divOuter">
	<div id="divInner">
		<input id="partitioned" type="text" maxlength="4" />
	</div>
<div>

＆＃13;

我认为这可以作为一个起点...... 希望这会有所帮助...

Answer 2

我知道这个问题很旧。当我试图为我的项目实现同样的目标时，我偶然发现了这一点。

我找不到我需要的东西。所以我自己从这里提出了想法

您可以将其与任意数量的字符一起使用，并且只要所有输入字段都位于div和id="otp"内，就无需更改javascript。

这是预览：

看看代码here

function OTPInput() {
  const inputs = document.querySelectorAll('#otp > *[id]');
  for (let i = 0; i < inputs.length; i++) {
    inputs[i].addEventListener('keydown', function(event) {
      if (event.key === "Backspace") {
        inputs[i].value = '';
        if (i !== 0)
          inputs[i - 1].focus();
      } else {
        if (i === inputs.length - 1 && inputs[i].value !== '') {
          return true;
        } else if (event.keyCode > 47 && event.keyCode < 58) {
          inputs[i].value = event.key;
          if (i !== inputs.length - 1)
            inputs[i + 1].focus();
          event.preventDefault();
        } else if (event.keyCode > 64 && event.keyCode < 91) {
          inputs[i].value = String.fromCharCode(event.keyCode);
          if (i !== inputs.length - 1)
            inputs[i + 1].focus();
          event.preventDefault();
        }
      }
    });
  }
}
OTPInput();

@import url('https://unpkg.com/tailwindcss@^1.0/dist/tailwind.min.css');
.form-control {
  -webkit-transition: none;
  transition: none;
  width: 32px;
  height: 32px;
  text-align: center
}

.form-control:focus {
  color: #3F4254;
  background-color: #ffffff;
  border-color: #884377;
  outline: 0;
}

.form-control.form-control-solid {
  background-color: #F3F6F9;
  border-color: #F3F6F9;
  color: #3F4254;
  transition: color 0.15s ease, background-color 0.15s ease, border-color 0.15s ease, box-shadow 0.15s ease;
}

.form-control.form-control-solid:active,
.form-control.form-control-solid.active,
.form-control.form-control-solid:focus,
.form-control.form-control-solid.focus {
  background-color: #EBEDF3;
  border-color: #EBEDF3;
  color: #3F4254;
  transition: color 0.15s ease, background-color 0.15s ease, border-color 0.15s ease, box-shadow 0.15s ease;
}

<div class="mb-6 text-center">
  <div id="otp" class="flex justify-center">
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="first" maxlength="1" />
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="second" maxlength="1" />
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="third" maxlength="1" />
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="fourth" maxlength="1" />
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="fifth" maxlength="1" />
    <input class="m-2 text-center form-control form-control-solid rounded focus:border-blue-400 focus:shadow-outline" type="text" id="sixth" maxlength="1" />
  </div>
</div>

Answer 3

我会保留这4个单独的字段方法，并为所有这些字段添加相同的事件处理程序，这将：

检查输入是否有效（在字符类中，您愿意接受）
检查您所在的字段，然后将焦点移至下一个字段或ok按钮。

你甚至可以为此编写一个单独的JS，然后重复使用它。

Answer 4

希望此解决方案对您有所帮助。您可以根据需要从 input 元素中删除 onfocus 事件。

<body>
  <head>
    <style>
      input[type=number] {
          height: 45px;
          width: 45px;
          font-size: 25px;
          text-align: center;
          border: 1px solid #000000;
      }
      input[type=number]::-webkit-inner-spin-button,
      input[type=number]::-webkit-outer-spin-button {
        -webkit-appearance: none;
        margin: 0;
      }
    </style>
    <script>
      function getCodeBoxElement(index) {
        return document.getElementById('codeBox' + index);
      }
      function onKeyUpEvent(index, event) {
        const eventCode = event.which || event.keyCode;
        if (getCodeBoxElement(index).value.length === 1) {
          if (index !== 4) {
            getCodeBoxElement(index+ 1).focus();
          } else {
            getCodeBoxElement(index).blur();
            // Submit code
            console.log('submit code ');
          }
        }
        if (eventCode === 8 && index !== 1) {
          getCodeBoxElement(index - 1).focus();
        }
      }
      function onFocusEvent(index) {
        for (item = 1; item < index; item++) {
          const currentElement = getCodeBoxElement(item);
          if (!currentElement.value) {
              currentElement.focus();
              break;
          }
        }
      }
    </script>
  </head>
  <body>
    <form>
        <input id="codeBox1" type="number" maxlength="1" onkeyup="onKeyUpEvent(1, event)" onfocus="onFocusEvent(1)"/>
        <input id="codeBox2" type="number" maxlength="1" onkeyup="onKeyUpEvent(2, event)" onfocus="onFocusEvent(2)"/>
        <input id="codeBox3" type="number" maxlength="1" onkeyup="onKeyUpEvent(3, event)" onfocus="onFocusEvent(3)"/>
        <input id="codeBox4" type="number" maxlength="1" onkeyup="onKeyUpEvent(4, event)" onfocus="onFocusEvent(4)"/>
    </form>
  </body>
</body>

Answer 5

这对我有效，不需要任何额外的JavaScript代码。

#partitioned {
  padding-left: 15px;
  letter-spacing: 42px;
  border: 0;
  background-image: linear-gradient(to left, black 70%, rgba(255, 255, 255, 0) 0%);
  background-position: bottom;
  background-size: 50px 1px;
  background-repeat: repeat-x;
  background-position-x: 35px;
  width: 220px;
  min-width: 220px;
}

#divInner{
  left: 0;
  position: sticky;
}

#divOuter{
  width: 190px; 
  overflow: hidden;
}

<div id="divOuter">
  <div id="divInner">
    <input id="partitioned" type="text" maxlength="4" onKeyPress="if(this.value.length==4) return false;"/>
  </div>
</div>

Answer 6

我不知道如何在html5中拆分输入，也许在css中你可以使用同一个类来控制输入，你可以输入样式，如：

div{
   text-align:center;
   background:#eee;
}
input{
    border: 0;
    outline: 0;
    background: transparent;
    border-bottom: 2px solid black;
    width: 100px;
    text-align:center;
    padding : 5px;
    margin-left:10px;
}
button{
  margin-top:20px !important;
  margin: 0 auto;
  color: white;
  border-radius: 4px;
  text-shadow: 0 1px 1px rgba(0, 0, 0, 0.2);
}

<div>
    <input class="form-control" placeholder="0" maxlength="1"  />
    <input class="form-control" placeholder="0" maxlength="1"  />
    <input class="form-control" placeholder="0" maxlength="1"  />
    <input class="form-control" placeholder="0" maxlength="1"  />
    <br><button type="button" onclick="myFunction()">Submit</button>
    <p id="optRes"></p>
</div>

定义myFunction（）并且您可以通过类获取数组：form-control，如果必须检查，则转换为string然后转换为int。有帮助吗？

Answer 7

如果使用AngularJS

，您可以使用以下指令

在您的HTML添加

中

<div otp-input-directive options="otpInput"></div>

在你的控制器中添加

$scope.otpInput={
        size:6,
        type:"text",
        onDone: function(value){
            console.log(value);
        },
        onChange: function(value){
            console.log(value);
        }
    };

Plunker link

UI component look and feel

https://github.com/amstel91/otp-input-directive

如何将输入字段分区为在屏幕上显示为单独的输入字段？

7 个答案: