无法执行任何类型的聚合功能。我有2个表与实体和一个表,其中包含每个实体的事务。
#qui
+--------+------------+
| idx | nbn |
+--------+------------+
| 44444 | 152357 |
| 55555 | 778852 |
| 66666 | 776856 |
+--------+------------+
#zea
+--------+------------+
| idx | nbn |
+--------+------------+
| 11111 | 159357 |
| 22222 | 753852 |
| 33333 | 745856 |
+--------+------------+
#trx
+--------+------------+---------+--------+
| idx | nbn |trx_amt |date |
+--------+------------+---------+--------+
| 11111 | 159357 |100 |01-01-16|
| 22222 | 753852 |200 |04-04-16|
| 33333 | 745856 |300 |11-05-16|
+--------+------------+---------+--------+
我的查询:
select
date
,qui_co = count (case when trx.idx in (select idx from qui) then trx_amt
,zea_co = count (case when trx.idx in (select idx from zea) then trx_amt
end)
from
trx
inner join (select idx from qui
union
select idx from zea) xxx
on trx.idx = xxx.idx
group by date
对于其他解决方案有任何想法吗?
答案 0 :(得分:0)
您应该可以使用左连接执行此操作:
select [date], count(q.idx), count(z.idx)
from trx t
left join qui q on t.idx=q.idx
left join zea z on t.idx=z.idx
group by [date]