API我必须使用sucks,并且总是返回HTTP 200.但有时会有正确的响应:
[{"blah": "blah"}, {"blah": "blah"}]
有时会出现错误:
{"error": "Something went wrong", "code": 123}
我正在使用带有Gson转换器和Rx适配器的Retrofit2:
final Api api = new Retrofit.Builder()
.baseUrl(URL)
.client(client)
.addCallAdapterFactory(RxJavaCallAdapterFactory.createWithScheduler(Schedulers.io()))
.addConverterFactory(GsonConverterFactory.create())
.build()
.create(Api.class);
现在,当我收到错误响应时,调用onError
处理程序时会出现以下异常:
java.lang.IllegalStateException: Expected BEGIN_ARRAY but was BEGIN_OBJECT at line 1 column 2 path $
at com.google.gson.stream.JsonReader.beginArray(JsonReader.java:350)
at com.google.gson.internal.bind.CollectionTypeAdapterFactory$Adapter.read(CollectionTypeAdapterFactory.java:80)
at com.google.gson.internal.bind.CollectionTypeAdapterFactory$Adapter.read(CollectionTypeAdapterFactory.java:61)
at retrofit2.converter.gson.GsonResponseBodyConverter.convert(GsonResponseBodyConverter.java:37)
at retrofit2.converter.gson.GsonResponseBodyConverter.convert(GsonResponseBodyConverter.java:25)
at retrofit2.ServiceMethod.toResponse(ServiceMethod.java:117)
at retrofit2.OkHttpCall.parseResponse(OkHttpCall.java:211)
at retrofit2.OkHttpCall.execute(OkHttpCall.java:174)
at retrofit2.adapter.rxjava.RxJavaCallAdapterFactory$RequestArbiter.request(RxJavaCallAdapterFactory.java:171)
at rx.internal.operators.OperatorSubscribeOn$1$1$1.request(OperatorSubscribeOn.java:80)
at rx.Subscriber.setProducer(Subscriber.java:211)
at rx.internal.operators.OperatorSubscribeOn$1$1.setProducer(OperatorSubscribeOn.java:76)
at retrofit2.adapter.rxjava.RxJavaCallAdapterFactory$CallOnSubscribe.call(RxJavaCallAdapterFactory.java:152)
at retrofit2.adapter.rxjava.RxJavaCallAdapterFactory$CallOnSubscribe.call(RxJavaCallAdapterFactory.java:138)
at rx.Observable.unsafeSubscribe(Observable.java:10144)
at rx.internal.operators.OperatorSubscribeOn$1.call(OperatorSubscribeOn.java:94)
at rx.internal.schedulers.CachedThreadScheduler$EventLoopWorker$1.call(CachedThreadScheduler.java:230)
at rx.internal.schedulers.ScheduledAction.run(ScheduledAction.java:55)
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:428)
at java.util.concurrent.FutureTask.run(FutureTask.java:237)
at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:272)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1133)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:607)
at java.lang.Thread.run(Thread.java:761)
我该如何解决?如果我可以在onError
处理程序中获得响应,我可以使用正确的错误模型类重新解析它。但似乎我无法得到原始的回应。
答案 0 :(得分:3)
您可以使用自定义Gson反序列化器将两个响应编组为单个对象类型。下面是假设您当前的响应类型为List<Map<String, String>>
的想法的草图,您需要根据实际的返回类型进行调整。我也假设API总是在成功时返回一个数组 -
public class MyResponse {
String error;
Integer code;
List<Map<String, String>> response;
}
interface MyApi {
@GET("/")
Observable<MyResponse> myCall();
}
private class MyResponseDeserializer implements JsonDeserializer<MyResponse> {
public MyResponse deserialize(JsonElement json, Type typeOfT, JsonDeserializationContext context)
throws JsonParseException {
MyResponse response = new MyResponse();
if (json.isJsonArray()) {
// It is an array, parse the data
Type responseType = new TypeToken<List<Map<String, String>>>(){}.getType();
response.response = context.deserialize(json, responseType);
} else {
// Not an array, parse out the error info
JsonObject object = json.getAsJsonObject();
response.code = object.getAsJsonPrimitive("code").getAsInt();
response.error = object.getAsJsonPrimitive("error").getAsString();
}
return response;
}
}
使用以上内容创建自定义Gson
Gson gson = new GsonBuilder()
.registerTypeAdapter(MyResponse.class, new MyResponseDeserializer())
.create();
在改装生成器中使用它 -
.addConverterFactory(GsonConverterFactory.create(gson))
您还应该更新界面以返回Observable<MyResponse>
。您现在可以在onNext
中获得成功和错误。您需要检查对象以确定它是否是成功的响应(response != null
)。