Question

我的xml文件中有大约200个editText。

我想在我的java文件中立即获取所有输入值。

如果没有找到所有200个ID，我有什么方法可以做到这一点。

Answer 1

试试这个：

private LinearLayout ll;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main_layout);

        ll=(LinearLayout)findViewById(R.id.ll_view);

        final int childcount = ll.getChildCount();
        for (int i = 0; i < childcount; i++) {
            View v = ll.getChildAt(i);
            if (v instanceof EditText) {
                Log.d("EditText Value", ((EditText) v).getText().toString());
            }
        }

    }

Answer 2

在linearlayout中创建200 EditText

LinearLayout mRlayout = (LinearLayout) findViewById(R.id.llMainLayout);
        LinearLayout.LayoutParams mRparams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT)
        for (int i = 0; i < 200; i++) {
            EditText myEditText = new EditText(context);
            myEditText.setLayoutParams(mRparams);
            mRlayout.addView(myEditText);
        }

在arraylist

中检索值

ArrayList<String> alEditTextInputs = new ArrayList<>();
    for(int j=0;j<mRlayout.getChildCount();j++){
        alEditTextInputs.add(((EditText)mRlayout.getChildAt(j)).getText().toString()); 
    }

Answer 3

您需要在父视图中以递归方式调用，以在视图中查找ViewGroup viewGroup = //Your parent layout it render your child view. int count = viewGroup .getChildCount(); for(int i =0;i<count;i++) { View v = viewGroup .getChildAt(i); if(v instanceof Edittext) { // you got the edittext EditText s = (EditText) v; Log.i("Item selected",s.getText().toString()); } }的实例。

<input id="status_action" name="status_action" value="1"  type="text" readonly="readonly">

<a href="javascript:void(0)" id="status_alert"  class="btn btn-success btn-xs"><i class="fa fa-envelope-o" aria-hidden="true"></i> unread </a>  

<script>
$(document).ready(function(){
 if ($('#status_action').val() == 0 ) {
    $('#status_alert').find('i').addClass('fa fa-envelope-open-o').removeClass('fa fa-envelope-o');  
 }
})
</script>

Answer 4

请点击此链接

Android Java立即获取所有editText

4 个答案: