我有三个字符串数组
string[] stringArray= {"AAA", "BBB", "CCC","DDD", "EEE","FFF","GGG","HHH" };
string[] stringArray1 = { "A", "B", "C","D", "E","F","G","H" };
string[] stringArray2 = { "BBB", "DDD","FFF","HHH" };
如何将stringArray2
与stringArray
进行比较,并找到匹配的索引号stringArray
。
找到索引后,我需要将其应用于stringArray1
并显示结果。
我尝试了以下代码,但未能获得匹配字符串
int j=0;
string line = null;
List<string> finalstring = new List<string>();
for (int i = 0; i < stringArray.Count; i++)
{
while(stringArray[i] == stringArray2[j])
{
line = stringArray2[i];
finalstring.Add(line);
j++;
}
}
答案 0 :(得分:1)
我想你必须尝试这样:
var result = stringArray1.Where(c => // iterating stringArray1
stringArray2.Where(x => stringArray.Contains(x)) // filtering stringArray2 elements
.Any(y=>y.Contains(c))).ToList(); // collect the final result
Working example供您参考
答案 1 :(得分:1)
int j=0;
string line = null;
List<string> finalstring = new List<string>();
for (int i = 0; i < stringArray.Length; i++)
//for (int i = 0; i < stringArray.Count; i++) // <-- Count is not proper way to get total elements in an array
{
j = 0; // <-- you failed to reinitialize 'j'
//while(stringArray[i] == stringArray2[j]) // <-- while is not proper way to compare
if(stringArray[i] == stringArray2[j])
{
//line = stringArray2[i];
//if only first charracter is needed
finalstring.Add(new string(stringArray2[i][0], 1));
//if complete string is needed
//finalstring.Add(stringArray2[i]);
j++;
}
}
以上不是进行比较的优化方法。您可以尝试使用HashSet class
string[] stringArray= {"AAA", "BBB", "CCC","DDD", "EEE","FFF","GGG","HHH" };
string[] stringArray1 = { "A", "B", "C","D", "E","F","G","H" };
string[] stringArray2 = { "BBB", "DDD","FFF","HHH" };
//convert string array to hashset
var hashSet = new HashSet<string>(stringArray);
int j=0;
string line = null;
List<string> finalstring = new List<string>();
for (int i = 0; i < stringArray2.Length; i++)
{
if(hashSet.Contains(stringArray2[i]))
{
//if only first charracter is needed
finalstring.Add(new string(stringArray2[i][0], 1));
}
}
答案 2 :(得分:1)
List<string> finalList = new List<string>();
stringArray.Select((value,index) => new { value, index })
.Where(num => stringArray2.Contains(num.value)).ToList()
.ForEach(num => finalList.Add(stringArray1[num.index]));
答案 3 :(得分:0)
您正在尝试比较同一索引上的元素,但您必须在stringArray2
中搜索stringArray
的元素。您可以使用Array.IndexOf在Array中查找所需的元素。
string[] stringArray= {"AAA", "BBB", "CCC","DDD", "EEE","FFF","GGG","HHH" };
string[] stringArray1 = { "A", "B", "C","D", "E","F","G","H" };
string[] stringArray2 = { "BBB", "DDD","FFF","HHH" };
int j=0;
string line = null;
List<string> finalstring = new List<string>();
for (int i = 0; i < stringArray2.Count(); i++)
{
if(Array.IndexOf(stringArray, stringArray2[i]) != -1)
{
int idx = Array.IndexOf(stringArray1, stringArray2[i][0].ToString());
if(idx!=-1)
finalstring.Add(stringArray1[idx]);
}
}
使用Linq 修改
var result2 = stringArray1.Where(c=>
stringArray2.Intersect(stringArray)
.Any(i=>i.Contains(c)));
答案 4 :(得分:0)
你可以通过Linq选择索引来做到这一点(where >= 0
过滤掉所有非匹配项):
string[] stringArray = { "AAA", "BBB", "CCC", "DDD", "EEE", "FFF", "GGG", "HHH" };
string[] stringArray1 = { "A", "B", "C", "D", "E", "F", "G", "H" };
string[] stringArray2 = { "BBB", "DDD", "FFF", "HHH" };
var matches = stringArray2
.Select(s => Array.FindIndex(stringArray, s2 => s2 == s))
.Where(i => i >= 0).Select(i => stringArray1[i])
.ToList();