Question

我正在开发一个网站
Red Sec
我在所有子域名中使用了1个帐户：

通告
论坛
博客
新闻
捐赠

通过将所有页面全部连接到http://red-sec.net/res/menu.php，所有页面都具有相同的样式，只有不同的内容。这是它的代码，因为你无法阅读它：

<?php
require 'connection.php';
function menu(){
  if(!isset($_SESSION['username'])){
  echo '<nav class="navbar navbar-default navbar-fixed-top shadow">
    <div class="container">
      <a href="http://red-sec.net" class="navbar-brand">Red-Sec.net</a>
      <ul class="nav navbar-nav">
        <li class="menuitem"><a href="http://red-sec.net">Home</a></li>
        <li class="menuitem"><a href="http://announcements.red-sec.net">Announcements</a></li>
        <li class="menuitem"><a href="http://forum.red-sec.net">Forum</a></li>
        <li class="menuitem"><a href="http://blog.red-sec.net">Blog</a></li>
        <li class="menuitem"><a href="http://news.red-sec.net">News</a></li>
        <li class="menuitem"><a href="http://donate.red-sec.net">Donate</a></li>
      </ul>
      <ul class="nav navbar-nav navbar-right">
        <li class="menuitem"><a href="http://red-sec.net/signup.php">Sign Up</a></li>
        <li class="menuitem"><a href="http://red-sec.net/Login.php">Log In</a></li>
      </ul>
    </div>
  </nav>
  <script
    src="https://code.jquery.com/jquery-3.1.1.js"
    integrity="sha256-16cdPddA6VdVInumRGo6IbivbERE8p7CQR3HzTBuELA="
    crossorigin="anonymous"></script>
  <script src=" ../js/menu.js"></script>
  <div class="container bg">
  <div class="row full">
  <div class="col-lg-8 bd">';
}else{
  $username = $_SESSION['username'];
  echo '<nav class="navbar navbar-default navbar-fixed-top shadow">
    <div class="container">
      <a href="http://red-sec.net" class="navbar-brand">Red-Sec.net</a>
      <ul class="nav navbar-nav">
        <li class="menuitem"><a href="http://beta.red-sec.net">Home</a></li>
        <li class="menuitem"><a href="http://announcements.red-sec.net">Announcements</a></li>
        <li class="menuitem"><a href="http://forum.red-sec.net">Forum</a></li>
        <li class="menuitem"><a href="http://blog.red-sec.net">Blog</a></li>
        <li class="menuitem"><a href="http://news.red-sec.net">News</a></li>
        <li class="menuitem"><a href="http://donate.red-sec.net">Donate</a></li>
      </ul>
      <ul class="nav navbar-nav navbar-right">
        <li class="menuitem"><a href="http://red-sec.net/profile.php">'.$username.'</a></li>
        <li class="menuitem"><a href="http://red-sec.net/Logout.php">Log Out</a></li>
      </ul>
    </div>
  </nav>
  <script
    src="https://code.jquery.com/jquery-3.1.1.js"
    integrity="sha256-16cdPddA6VdVInumRGo6IbivbERE8p7CQR3HzTBuELA="
    crossorigin="anonymous"></script>
  <script src="../js/menu.js"></script>
  <div class="container bg">
  <div class="row full">
  <div class="col-lg-8 bd">';
}
}
function endbd(){
    require'connection.php';
  echo '</div>
  <div class="col-lg-4 bd sidebar">
  <h2 class="title">Latest News Post</h2>
<hr class="under">';
$query = "SELECT * FROM news ORDER BY date DESC LIMIT 1";
$run = mysqli_query($connect,$query);
if(!$run){
    echo 'sorry';
}
$row = mysqli_fetch_array($run);
  $article_id = $row['article_id'];
  $user_id = $row['user_id'];
  $title = $row['title'];
  $content = $row['content'];
  $date = $row['date'];
  $query = "SELECT username FROM users WHERE ID = '$user_id'";
  $test = mysqli_query($connect,$query);
  $row2 = mysqli_fetch_array($test);
  $user_name = $row2['username'];
  echo '<div class="row">
  <div class="col-lg-12"><h3 class="para"><a class="para" href="/news/article.php?id='.$article_id.'">'.$title.'</a></h3>
  <p class="para">Written by: '.$user_name.'</p>
  </div>
  </div>
  </div>
  </div>
  </div>';
}
 ?>

我注意到当您登录主页并转到子域时，菜单会显示注册或登录，而不是您应该执行的用户名。
但是，当您单击注册或登录时，只需刷新页面并显示您的用户名和旁边的注销选项。意味着会话在子域中工作，但由于某种原因，它首先没有显示，所以你必须刷新它？谁能解释为什么会这样？

编辑：
以下是我如何使用res / menu.php

的示例

<?php
session_start();
include 'res/connection.php';
include 'res/menu.php';
?>
<!DOCTYPE html>
<html>
<head>
  <title>R3D S3C | Home page</title>
  <link rel="stylesheet" type="text/css" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css"/>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script>
  <link rel="stylesheet" type="text/css" href="css/style1.css"/>
  <link href='https://fonts.googleapis.com/css?family=Roboto' rel='stylesheet' type='text/css'>
</head>
<body>
<?php menu(); ?>
<h2 class="title">Red Sec</h2>
<p class="para">Long Lorem Ipsum text goes here...</p>
<?php endbd(); ?>
</body>
</html>

编辑2：
根据要求登录页面：

<?php
session_start();
include 'res/connection.php';
include 'res/menu.php';
if(isset($_SESSION['username'])){
  header('Location: profile.php');
}
?>
<!DOCTYPE html>
<html>
<head>
  <link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css" rel="stylesheet" integrity="sha384-BVYiiSIFeK1dGmJRAkycuHAHRg32OmUcww7on3RYdg4Va+PmSTsz/K68vbdEjh4u" crossorigin="anonymous">
  <link href="css/style1.css" rel="stylesheet" type="text/css"/>
  <title>Red Sec | Login</title>
</head>
<body>
      <?php
      $error = "";
      $userErr = "";
      $passErr = "";
        if(isset($_POST['Login'])){
          $username = $_POST['username'];
          $password = $_POST['password'];
          if($username == ""){
            $userErr = "Username cannot be empty";
          }else{
            $userErr = "";
          }
          if($password == ""){
            $passErr = "Password cannot be empty";
          }else if(strlen($password) > 32){
              $passErr = "Password too long";
          }
          else{
            $passErr = "";
          }
          if($userErr == "" && $passErr == ""){
            $sql = "SELECT * FROM users WHERE username = '$username' OR email = '$username'";
            $result = mysqli_query($connect,$sql);
            if(!$result){
              $error = "Unable to retrieve information, please try again later.";
            }else if(mysqli_num_rows($result) < 1){
              $error = "This account does not exist!";
            }else{
              $row = mysqli_fetch_array($result);
              $dbpassword = $row['password'];
              $salt = $row['salt'];
              $password = crypt($password,$salt);
              if($password == $dbpassword){
                $_SESSION['id'] = $row['ID'];
                $_SESSION['username'] = $row['username'];
                $_SESSION['email'] = $row['email'];
                $error = "";
                echo "<script>window.location = 'profile.php'</script>";
              }else{
                $error = "username or email / Password combination is wrong!";
              }
            }
          }else{
            $error = "";
          }
        }
      ?>
      <?php menu(); ?>
      <h2 class="title">Log In</h2>
        <form id="register-form" class="text-left" method="post">
            <div class="login-form-main-message"></div>
            <div class="main-login-form">
                <div class="login-group">
          <p class="error"><?php echo $error; ?></p>
                    <div class="form-group">
                        <label for="reg_username" class="sr-only">Username or Email</label>
                        <input type="text" class="form-control" id="reg_username" name="username" placeholder="Username or Email">
            <p class="error"><?php echo $userErr; ?></p>
                    </div>
                    <div class="form-group">
                        <label for="reg_password" class="sr-only">Password</label>
                        <input type="password" class="form-control" id="reg_password" name="password" placeholder="password">
            <p class="error"><?php echo $passErr; ?></p>
          </div>
          <div class="move">
                <button class="button btn btn-primary" value="Login" name="Login">Login</button>
            </div>
    </div>
</div>
        </form>
    <?php endbd(); ?>
</body>
</html>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js" integrity="sha384-Tc5IQib027qvyjSMfHjOMaLkfuWVxZxUPnCJA7l2mCWNIpG9mGCD8wGNIcPD7Txa" crossorigin="anonymous"></script>

Answer 1

请阅读这篇文章

https://stackoverflow.com/a/11030316/6329312

PHP：

<?php
session_set_cookie_params(0, '/', '.mywebsite.com');
session_start();
//Code...
?>

Answer 2

尝试这种方法

    <?php
    session_name("my_session");
    session_set_cookie_params(0,"/",".yoursite.com");
    session_start();

并且您应该能够在整个网站的子域中进行会话

Answer 3

我解决了所有感兴趣的人注意事项
你需要这样做：

ini_set('session.cookie_domain', '.yourdomainhere.com');
session_set_cookie_params(0, '/', '.yourdomainhere.com');

这对我来说是两个混合，你必须将它们放在每个调用php函数session_start（）的页面中; 你必须把它放在session_start（）之前; 它对我有用:) 希望它也适合你

会话在子域中可用，但未在物理上显示

3 个答案: