我的postgres数据库中有一些JSON,它位于一个名为site_content
的表中,该表有两行,id
和content
,在content
中是我的地方存储我的JSON。我希望能够找到一个给出他身份的玩家,我的玩家存储在密钥series
下,因为这是从JSON创建我的图表所需的密钥。
以下是我目前使用的查询:
Blocking.get {
sql.firstRow("""SELECT * from site_content where content -> 'playersContainer' -> 'series' -> 'id' = ${id} """)
}.map { row ->
log.info("row is: ${row}")
if (row) {
objectMapper.readValue(row.getAt(0).toString(), Player)
}
}
}
但是我收回了这个错误:
org.postgresql.util.PSQLException:错误:运算符不存在: json =字符变化提示:没有运算符匹配给定的名称 和参数类型。您可能需要添加显式类型转换。
以下是我的JSON示例:
"id": "${ID}",
"team": {
"id": "123",
"name": "Shire Soldiers"
},
"playersContainer": {
"series": [
{
"id": "1",
"name": "Nick",
"teamName": "Shire Soldiers",
"ratings": [
1,
5,
6,
9
],
"assists": 17,
"manOfTheMatches": 20,
"cleanSheets": 1,
"data": [
3,
2,
3,
5,
6
],
"totalGoals": 19
},
{
"id": "2",
"name": "Pasty",
"teamName": "Shire Soldiers",
"ratings": [
6,
8,
9,
10
],
"assists": 25,
"manOfTheMatches": 32,
"cleanSheets": 2,
"data": [
3,
5,
7,
9,
10
],
"totalGoals": 24
}
]
}
我在这个项目中使用Groovy,但我想这只是我遇到问题的一般JSON postgres语法。
答案 0 :(得分:3)
你是对的,这是SQL语法的问题。纠正你的疑问:
select * from json_test where content->'playersContainer'->'series' @> '[{"id":"1"}]';
完整示例:
CREATE TABLE json_test (
content jsonb
);
insert into json_test(content) VALUES ('{"id": "1",
"team": {
"id": "123",
"name": "Shire Soldiers"
},
"playersContainer": {
"series": [
{
"id": "1",
"name": "Nick",
"teamName": "Shire Soldiers",
"ratings": [
1,
5,
6,
9
],
"assists": 17,
"manOfTheMatches": 20,
"cleanSheets": 1,
"data": [
3,
2,
3,
5,
6
],
"totalGoals": 19
},
{
"id": "2",
"name": "Pasty",
"teamName": "Shire Soldiers",
"ratings": [
6,
8,
9,
10
],
"assists": 25,
"manOfTheMatches": 32,
"cleanSheets": 2,
"data": [
3,
5,
7,
9,
10
],
"totalGoals": 24
}
]
}}');
select * from json_test where content->'playersContainer'->'series' @> '[{"id":"1"}]';
答案 1 :(得分:-1)
可能会有所帮助:在sql语句中,我添加了这个' cast'我有json字段:
INSERT INTO map_file(type, data)
VALUES (?, CAST(? AS json))
RETURNING id
'数据的数据类型'到map_file表是:json