Question

Array (
        [0] => Array (
            [Name] => Banana
            [Percentage] => 25
            [Sum] => 70
        )
        [1] => Array (
            [Name] => Banana
            [Percentage] => 25
            [Sum] => 168
        )
        [2] => Array (
            [Name] => Apple
            [Percentage] => 14
            [Sum] => 8
        )
    )

如果键[Name]和[Percentage]与数组中的另一个键相似，如何合并值？

例如，我搜索的内容如下：

Array (
    [0] => Array (
        [Name] => Banana
        [Percentage] => 25
        [Sum] => 238
    )
    [1] => Array (
        [Name] => Apple
        [Percentage] => 14
        [Sum] => 8
    )
)

这是我尝试的内容：

foreach($myArray as $value){
    $Name = $value['Name'];
    if(isset($result[$Name]))
        $index = count($result[$Name]);
    else
        $index = 1;

    $result['Name'] = $Name;
    $result['Percentage'] = $value['Percentage'];
    $result['Sum'] += $value['Sum'];        
}
$result = array_values($result);

感谢。

Answer 1

你现在拥有的问题是你只是复制原始数组中已有的内容，除非你使用val arrayOfArrayOfAnys=Array( Array("aString",0L ,3.14159), Array("bString",9876543210L,2.71828) ) val rddOfRows=spark.sparkContext.parallelize(arrayOfArrayOfAnys).map(f=>Row.fromSeq(f.toSeq)) /* If one knows the datatypes, for instance from JDBC queries as to RDBC column metadata: * Consider constructing the schema from an Array[StructField]. This would allow looping over * the columns, with a match statement applying the appropriate sql datatypes as the second * StructField arguments. */ val sf=new Array[StructField](3) sf(0)=StructField("colOfStrings",StringType) sf(1)=StructField("colOfLongs" ,LongType ) sf(2)=StructField("colOfDoubles",DoubleType) val df=spark.sqlContext.createDataFrame(rddOfRows,StructType(sf.toList)) df.show投入失败的总和。请参阅以下带有符号的新示例：

$result['Sum'] += $value['Sum'];

Answer 2

基本上你想要做的是遍历数组并将当前项目与前一项目进行比较，随时构建一个独特项目数组。

如果Name和Percentage在当前项和上一项之间相等，则只需将当前项的总和添加到上一项。如果没有，那么只需将当前项添加到新数组。

这对你有用：

$newArray = Array();

foreach ($myArray as $currentItem) {

    if (isset($prevItem) && $currentItem['Name'] == $prevItem['Name'] && $currentItem['Percentage'] == $prevItem['Percentage']) {
        // append sum to previous item
        $prevItem['Sum'] += $currentItem['Sum'];
    } else {
        // add current item to array
        $newArray[] = $currentItem;
        $lastIndex = count($newArray) - 1;
        $prevItem = &$newArray[$lastIndex];
    }
}

注意：这假定数组已按名称和百分比排序。

如果某些键相似，则合并数组中的数据

2 个答案: