Question

我正在设计一个电报机器人。我想展示一些链接，例如

1- wkpviana

2- vianahosting

当用户点击它时，打开

<?php
...
$sLink = "";
foreach($Links as $Row){
    $sLink .= "<a href='".$Row->link_url."'>".$Row->link_name."</a>";
}
$Text = $sLink;
...
$URL = "https://api.telegram.org/bot".$Token."/sendMessage?chat_id=".$ChatID."&text=".$Text."&reply_markup=".json_encode($KB);
file_get_contents($URL);
?>

在浏览器中

。我怎么能在PHP中创建它？我的部分代码是：

override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
    for touch: AnyObject in touches {

        let pointOfTouch = touch.location(in: self)

        let nodeUserTapped = atPoint(pointOfTouch)

        if nodeUserTapped.name == "PauseButton" {
            if (self.isPaused == false) {
                pauseGame()
            }
        }

        if nodeUserTapped.name == "ResumeButton" {
            if (self.isPaused == true) {
                resumeGame()
            }

        }
    }
}


// MARK: - pauseGame
func pauseGame() {
    self.isPaused = true
    currentGameState = gameState.pauseGame
    self.physicsWorld.speed = 0
    self.speed = 0.0
    if (backgroundMusicIsOn == true) {
        backingAudio.stop()
    }
    if resumeButton.isHidden == true {
        resumeButton.isHidden = false
    }
    if pauseButton.isHidden == false {
        pauseButton.isHidden = true
    }
}


// MARK: - resumeGame
func resumeGame() {
    self.isPaused = false
    currentGameState = gameState.inGame
    self.physicsWorld.speed = 1
    self.speed = 1.0
    if (backgroundMusicIsOn == true) {
        backingAudio.play()
    }
    if resumeButton.isHidden == false {
        resumeButton.isHidden = true
    }
    if pauseButton.isHidden == true {
        pauseButton.isHidden = false
    }
}

Answer 1

您似乎尝试使用<a>代码发送链接，该代码工作正常，但要求您使用parse_mode=html参数，如文档所述here.

我相信它看起来有点像这样：

$URL = "https://api.telegram.org/bot".$Token."/sendMessage?chat_id=".$ChatID."&text=".$Text."&parse_mode=HTML&reply_markup=".json_encode($KB);

如何在电报机器人中创建链接

1 个答案: