Question

目前我的NumberOfDaysBetweenPurchases每ItemNumber AccountNumber位ItemNumber|AVERAGENumberOfDaysBetweenPurchases。我试图联合NumberOfDaysBetweenPurchases

我有两个问题。 1，我找不到一种方法来获得订单之间所有天数的平均值。 2，如果没有按帐号或购买日期订购/分组，我无法显示。因此，每次客户订购产品时，它总是会显示数百万行。

以下是我用来获取datediff(day, lag(OrderDate,1) over (partition by AccountNumber order by OrderDate), OrderDate) as [NumOfDaysBetweenOrdersByAccountNum]：

的内容

ItemNumbers

如何整合ItemNumber | AvgNumberOfDaysBetweenOrdersByAccountNumber 12345 6 452234 45 5235 3以便它们只显示一次以及按帐号排序的平均天数？我希望它能像这样出现：

ItemNumber | NumberDays(...)  | OrderDate | AccountNumber
123           0                   ----        101010
123           1                   ----        101010
123           4                   ----        101010
123           7                   ----        101010
123           8                   ----        101010

以下是我当前信息的示例（数百万行）：

$list = ["fa1", "fa2", "fa3", "fa4", "fa5"];
PutFileContentList($list);
function PutFileContentList(array $list) {
    globals $file, $pcarray, $voiparray;
    foreach ($list as $varname) {
        $line = isset($GLOBALS[$varname]) ? $GLOBALS[$varname] : "";
        if ($line == "PC") {
            file_put_contents($file, $pcarray . FILE_APPEND);
        }
        if ($line == "VOIP") {
            file_put_contents($file, $voiparray . FILE_APPEND);
        }
    }
}

Answer 1

根据我对你的问题的理解，试试这个。

WITH cte AS ( SELECT ItemNumber, ItemNumber, AccountNumber, datediff(day, lag(OrderDate,1) over (partition by AccountNumber order by OrderDate), OrderDate) as [NumOfDaysBetweenOrdersByAccountNum] ) SELECT ItemNumber , AVG(NumberOfDaysBetweenOrdersByAccountNum) FROM cte GROUP BY ItemNumber

尝试使用NumberOfDaysBetweenOrders

1 个答案: