ReactNative iOS Spotify SDK

Question

我正在关注Spotify SDK tutorial，并尝试为我的应用程序制作RN模块。这是我的SpotifyModule.m代码：

#import "SpotifyModule.h"
#import "React/RCTLog.h"
#import "React/RCTBridge.h"


@implementation SpotifyModule


RCT_EXPORT_MODULE()


+ (id)sharedManager {
  static SpotifyModule *sharedManager = nil;
  @synchronized(self) {
    if (sharedManager == nil)
      sharedManager = [[self alloc] init];
  }
  return sharedManager;
}


RCT_EXPORT_METHOD(authenticate:(RCTResponseSenderBlock)callback)
{
  // Your implementation here
  RCTLogInfo(@"authenticate");
  self.auth = [SPTAuth defaultInstance];
  // The client ID you got from the developer site
  self.auth.clientID = @"8fff6cbb84d147e383060be62cec5dfa";
  // The redirect URL as you entered it at the developer site
  self.auth.redirectURL = [NSURL URLWithString:@"my-android-auth://callback"];
  // Setting the `sessionUserDefaultsKey` enables SPTAuth to automatically store the session object for future use.
  self.auth.sessionUserDefaultsKey = @"current session";
  // Set the scopes you need the user to authorize. `SPTAuthStreamingScope` is required for playing audio.
  self.auth.requestedScopes = @[SPTAuthPlaylistReadPrivateScope, SPTAuthUserReadPrivateScope];

  //save the login callback
  SpotifyModule *spotifyModule = (SpotifyModule *)[SpotifyModule sharedManager];
  spotifyModule.loginCallback = callback;

  //setup event dispatcher
  spotifyModule.eventDispatcher = [[RCTEventDispatcher alloc] init];
  [spotifyModule.eventDispatcher setValue:self.bridge forKey:@"bridge"];

  // Start authenticating when the app is finished launching
  dispatch_async(dispatch_get_main_queue(), ^{
    [self startAuthenticationFlow];
  });
}

- (void)startAuthenticationFlow
{
  // Check if we could use the access token we already have
  if ([self.auth.session isValid]) {
    // Use it to log in
      SpotifyModule *spotifyModule = (SpotifyModule *)[SpotifyModule sharedManager];
      NSString *accessToken = self.auth.session.accessToken;
      spotifyModule.loginCallback(@[accessToken]);
  } else {
    // Get the URL to the Spotify authorization portal
    NSURL *authURL = [self.auth spotifyWebAuthenticationURL];
    // Present in a SafariViewController
    self.authViewController = [[SFSafariViewController alloc] initWithURL:authURL];
    UIViewController *rootViewController = [UIApplication sharedApplication].delegate.window.rootViewController;

    [rootViewController presentViewController:self.authViewController animated:YES completion:nil];
  }
}

- (BOOL)  application:(UIApplication *)app
          openURL:(NSURL *)url
          options:(NSDictionary *)options
{
  // If the incoming url is what we expect we handle it
  if ([self.auth canHandleURL:url]) {
    // Close the authentication window
    [self.authViewController.presentingViewController dismissViewControllerAnimated:YES completion:nil];
    self.authViewController = nil;
    // Parse the incoming url to a session object
    [self.auth handleAuthCallbackWithTriggeredAuthURL:url callback:^(NSError *error, SPTSession *session) {
      if (session) {
        // Send auth token
        SpotifyModule *spotifyModule = (SpotifyModule *)[SpotifyModule sharedManager];
        NSString *accessToken = session.accessToken;
        spotifyModule.loginCallback(@[accessToken]);      }
    }];
    return YES;
  }
  return NO;
}

@end

我想从RN端使用它的方式是调用身份验证，带有访问令牌的回调。我在Android上做得很好。

  Native.authenticate(function(token) {
    store.dispatch(actions.loginSuccess(token));
  });

在iOS上，使用上面的代码，我进入了附加的屏幕，当点击“确定”时，我收到以下错误：

  

SpotiFind [5475：29641] ***因未捕获的异常而终止应用   'NSInvalidArgumentException'，原因：'+ [SpotifyModule   application：openURL：sourceApplication：annotation：]：unrecognized   选择器发送到类0x10cb406f8'

因此，从我最小的ObjectiveC理解，它试图调用一个不同的方法，而不是教程指示实现的方法。 关于如何使这项工作的任何建议？

如果它有任何相关性，我会针对iOS 10构建，并使用最新的Spotify iOS SDK

p.s我意识到这个名字可能反对某些版权，它只是发展的温度：）

Answer 1

感谢您的提示（在评论中），我们设法使Spotify身份验证与React-native一起使用。

我们使用您的Pastebin中的代码创建一个可重复使用的模块，以便没有人不再浪费时间。

您可以在此处找到该模块：emphaz/react-native-ios-spotify-sdk

有一个设置教程，我们甚至创建了一个boilerplate project

非常感谢Giannis！