我有以下代码,它应该只获取所有活动接口的IPv4地址,但它仍会在某些计算机上返回IPv6地址。
public static List<List> getIpAddress() {
List<String> ip = new ArrayList<>();
List<List> ipRefined = new ArrayList<>();
try {
Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
while (interfaces.hasMoreElements()) {
NetworkInterface iface = interfaces.nextElement();
if (iface.isLoopback() || !iface.isUp())
continue;
Enumeration<InetAddress> addresses = iface.getInetAddresses();
while(addresses.hasMoreElements()) {
ip.add(addresses.nextElement().getHostAddress());
}
}
} catch (SocketException e) {
throw new RuntimeException(e);
}
for(int x = 0; x < ip.size(); x++){
if(ip.get(x).contains("%")){
try {
if (ip.get(x + 1).contains(".")) {
List<String> tempList = new ArrayList<>();
tempList.add(ip.get(x).substring(ip.get(x).indexOf("%") + 1));
tempList.add(ip.get(x + 1));
ipRefined.add(tempList);
}
} catch (IndexOutOfBoundsException ae) {
}
}
}
return ipRefined;
}
我尝试使用System.setProperty("java.net.preferIPv4Stack" , "true");
指定仅使用IPv4,但这只会导致getIpAddress()
返回空列表。如何在不使用字符串操作的情况下获取活动接口的IPv4?
修改
使用System.setProperty("java.net.preferIPv4Stack" , "true");
始终会导致getIpAddress()
返回空列表。
答案 0 :(得分:1)
此类表示网络接口地址。简而言之,当地址是IPv4时,它是IP地址,子网掩码和广播地址。 IPv6地址的IP地址和网络前缀长度。
这是我的代码:
Enumeration<NetworkInterface> interfaces = NetworkInterface.getNetworkInterfaces();
while (interfaces.hasMoreElements()) {
NetworkInterface networkInterface = interfaces.nextElement();
System.out.println(String.format("networkInterface: %s", networkInterface.toString()));
if (!networkInterface.isUp()) {
continue;
}
for (InterfaceAddress interfaceAddress : networkInterface.getInterfaceAddresses()) {
int npf = interfaceAddress.getNetworkPrefixLength();
InetAddress address = interfaceAddress.getAddress();
InetAddress broadcast = interfaceAddress.getBroadcast();
if (broadcast == null && npf != 8) {
System.out.println(String.format("IPv6: %s; Network Prefix Length: %s", address, npf));
} else {
System.out.println(String.format("IPv4: %s; Subnet Mask: %s; Broadcast: %s", address, npf, broadcast));
}
}
}