Question

var dataString = JSON.stringify(formDara);
    console.log(dataString);
$.ajax({
    url: urL,
    type: "POST",
    cache: false,
    data: dataString,
    success: function (data) {
        console.log(data);
    }
});

这里，formData是一个对象。 console.log（dataString）OUTPUT：

{"library_fee":"100","lab_fee":"200","tution_fee":"300","admission_fee":"400"}

但是我的控制器没有价值。 Codeigniter控制器ACTION方法：

public function set_fees_structure($id) {
    $data = array();
    $data["admission_fee"] = $this->input->post("admission_fee", TRUE);
    $data["tution_fee"] = $this->input->post("tution_fee", TRUE);
    $data["library_fee"] = $this->input->post("library_fee", TRUE);
    $data["lab_fee"] = $this->input->post("lab_fee", TRUE);
    echo 'I m set fees structures ' . $id;
    echo '<pre>';
    print_r($data);
    exit();
}

Answer 1

试试这个@Ikram Hasib

方法1

    var jsonFile = {
      "coord": {
        "lon": -88.64,
        "lat": 35.44
      },
      "weather": [{
        "id": 701,
        "main": "Mist",
        "description": "mist",
        "icon": "50n"
      }]
    }
    $.ajax({
      type: "POST",
      url: url,
      data: JSON.stringify({
        jsonFile
      }),
      dataType: "json",
      contentType: "application/json",
      Accept: 'application/json; charset=utf-8',
      success: function(data) {
        console.log(data);
      }
    });

方法2

 var jsonFile = {
   "coord": {
     "lon": -88.64,
     "lat": 35.44
   },
   "weather": [{
     "id": 701,
     "main": "Mist",
     "description": "mist",
     "icon": "50n"
   }]
 }

 $.post(url, JSON.stringify({
     jsonFile
   }))
   .done(function(data) {
     console.log(data);
   });

JSON.stringify（）对象在Codeigniter中的ajax调用中不起作用

1 个答案: