如何等待forEach循环执行的所有递归函数调用都完成

Question

我怎样才能在代码中的所需位置等待，直到treeData上的所有处理完成为止？

var treeData = $scope.rawData;

if ($scope.treeExpanded) {
  //expand tree
  if (treeData && treeData.children) {
    treeData.children.forEach(toggleAll);
  }

  //how to wait here until all recursion calls are finished?
  //console.log(treeData) will show a non modified object equals to $scope.rawData

}

function toggle(d) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
  }
}

function toggleAll(d) {
  if (d && d.children) {
    d.children.forEach(toggleAll);
    toggle(d);
  }
}

Answer 1

1. 最简单的方法是添加一个函数调用计数器
2. 执行所有函数调用后，请使用回调并继续进行。
＆＃13;
＆＃13;
var treeData = $scope.rawData, callCompleted;

if ($scope.treeExpanded) {
  //expand tree
  if (treeData && treeData.children) {
    callsCompleted = 0;
    treeData.children.forEach(toggleAll);
  }

  //how to wait here until all recursion calls are finished?
  //console.log(treeData) will show a non modified object equals to $scope.rawData

}

function toggleCompleted() {
    // Do your processing here...
}

function toggle(d, noOfCalls, callBack) {
  if (d.children) {
    d._children = d.children;
    d.children = null;
    callsCompleted += 1;
    if(noOfCalls === callsCompleted) {
        // all calls are completed
        callBack();
    }
  }
}

function toggleAll(d) {
  if (d && d.children) {
    d.children.forEach(toggleAll);
    toggle(d, d.length, trackToggleCompletion);
  }
}
＆＃13;
＆＃13;
＆＃13;