Question

目前我有一个列表，我会遍历它，如果满足条件，我会清除数据（请参阅foreach）。

当前代码但不是我想要的，我想使用强类型

public class ViewCommonItemVM
{
    public string Name { get; set; }
    public List<string> Data { get; set; }
    public string Bullet { get; set; }

    public ViewCommonItemVM()
    {
        Data = new List<string>();
    }
}


List<ViewCommonItemVM> commons = new List<ViewCommonItemVM>();

commons.Add( new ViewCommonItemVM { Name = "Projects", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Companies", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Schools", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Hobbies", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Locations", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Interests", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Stuff", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Things", Data = someListHere });
commons.Add( new ViewCommonItemVM { Name = "Somelist", Data = someListHere });

foreach (var common in commons.Where(c => c.Data.Count != 0))
{
    count++;
    if (count > 4 && common.Data.Count != 0)
        common.Data.Clear();
}

但我希望从stronly类型中受益，所以

想要

对象

public class ViewCommonVm
{
    public ViewCommonItemVM Projects {get;set;}
    public ViewCommonItemVM Companies {get;set;}
    public ViewCommonItemVM Schools {get;set;}
    public ViewCommonItemVM Hobbies {get;set;}
    public ViewCommonItemVM Locations {get;set;}
    public ViewCommonItemVM Interests {get;set;}
    public ViewCommonItemVM Stuff {get;set;}
    public ViewCommonItemVM Things {get;set;}
    public ViewCommonItemVM Somelist {get;set;}
}

public class ViewCommonItemVM
{
    public string Name { get; set; }
    public List<string> Data { get; set; }
    public string Bullet { get; set; }
}


// Here it should iterated trough the object, and after 
// 4 lenght properties != 0, clear the property list

我怎样才能做到这一点？

Answer 1

你能用linq来解决这个问题吗？

这样的事可能有效

commons.Where(x => x.Data.Any()).Skip(4).ToList().ForEach(x => x.Data = new List<string>());

Answer 2

必须使用反射：

            void MyClear()
        {
            int count = 0;
            foreach (System.Reflection.PropertyInfo item in typeof(ViewCommonVm).GetProperties())
            {
                ViewCommonItemVM common = (ViewCommonItemVM)item.GetValue(this);
                if (common.Data.Count() != 0)
                {
                    count++;
                    if (count > 4 && common.Data.Count != 0)
                        common.Data.Clear();
                }
            }
        }

比原版慢一点。如果您的属性不是ViewCommonItemVM，请更改代码以检查item.GetValue（this）是否产生正确的类型。

迭代对象属性并在条件满足时更新

2 个答案: