Question

我希望有一个包含客户唯一键的列，由数字+字符按升序组成。是否有可能以某种方式指示Oracle生成许多记录，从1a到1z，然后是2a到2z等，直到300000z：

CUSTOMER_NUM
------------
10a

10b

10c

.

.

10z

11a

11b

.

到目前为止我达到的最佳状态是这样的：

select ROUND(DBMS_RANDOM.VALUE(9,21)), dbms_random.string('l', 1) from dual;

有什么想法吗？我想生成至少有300000条记录的测试表。

谢谢！

Answer 1

您可能需要以下内容：

select alpha || num
from 
(select substr('qwertyuiopasdfghjklzxcvbnm', level, 1) as alpha from dual connect by level <= 26)
cross join 
(select level as num from dual connect by level <= 2)
order by num, alpha

第一个查询使用包含所有字符的字符串，并将其拆分为包含单个字符的26行。

第二个查询生成一定数量的数字以与字符连接。

Answer 2

你可以尝试这个：

WITH n AS 
    (SELECT LEVEL AS Num FROM dual CONNECT BY LEVEL < 10),
c AS 
    (SELECT CHR(LEVEL + 96) AS alpha FROM dual CONNECT BY LEVEL <= 26)
SELECT num||alpha
FROM n 
    CROSS JOIN c;

Answer 3

下面的查询应该会给你想要的结果。

WITH
TABLE1 AS (SELECT LEVEL PART_1   FROM DUAL CONNECT BY LEVEL <= 300000),
TABLE2 AS (SELECT CHR(LEVEL+96) AS PART_2 FROM DUAL CONNECT BY LEVEL <27)
SELECT PART_1||PART_2 AS KEY_ID FROM TABLE1,TABLE2

Oracle - 生成包含字母数字和字符升序的记录

3 个答案: