Question

我有一个带有多个提交按钮的简单表单。如何更改java脚本以查看单击的按钮。感谢

<form class="contact" role="form" data-toggle="validator" id="testform">
    <div class="form-group">
        <label for="inputName" class="control-label">Name</label>
        <input type="text" class="form-control" id="inputName" name="inputName" placeholder="Cina Saffary" required>
        <div class="help-block with-errors"></div>
    </div>
    <div class="form-group">
        <button class="btn btn-success" type="submit" id="save1" value="save1">save1</button>
        <button class="btn btn-success" type="submit" id="save2" value="save2">save2</button>
    </div>
</form>


$('#testform').validator().on('submit', function (e) { (e.isDefaultPrevented()) { 
  alert("failure!"); 
} else { 
  // if save1 clicked, alert("save1 was clicked"); 
  // if save2 clicked, alert("save2 was clicked"); 
} 
});

Answer 1

你可以得到这样的按钮值：

 RelativeLayout r1 = (RelativeLayout) findViewById(R.id.relativelayout1);
 r1.setBackgroundResource(R.drawable.sample);

您还需要为按钮再添加一个事件

var val = $("button[type=submit][clicked=true]").val();

DEMO

参考：How can I get the button that caused the submit from the form submit event?

Bootstrap验证器表单中的多个按钮

1 个答案: