这个问题基于我做过的宠物项目和这个SO主题。在Akka HTTP路由定义中,我启动了一个长时间运行的进程,当然我想在不阻塞用户的情况下这样做。我可以使用下面的代码片段来实现这一目标:
blocking-io-dispatcher {
type = Dispatcher
executor = "thread-pool-executor"
thread-pool-executor {
fixed-pool-size = 16
}
throughput = 1
}
complete {
Try(new URL(url)) match {
case scala.util.Success(u) => {
val src = Source.fromIterator(() => parseMovies(u).iterator)
src
.via(findMovieByTitleAndYear)
.via(persistMovies)
.toMat(Sink.fold(Future(0))((acc, elem) => Applicative[Future].map2(acc, elem)(_ + _)))(Keep.right)
// run the whole graph on a separate dispatcher
.withAttributes(ActorAttributes.dispatcher("blocking-io-dispatcher"))
.run.flatten
.onComplete {
_ match {
case scala.util.Success(n) => logger.info(s"Created $n movies")
case Failure(t) => logger.error(t, "Failed to process movies")
}
}
Accepted
}
case Failure(t) => logger.error(t, "Bad URL"); BadRequest -> "Bad URL"
}
}
如果我已经解决了问题,那么问题是什么?问题是我不确定如何设置超时。图表的执行会创建一个Future
,直到专用blocking-io-dispatcher
完成为止。如果我添加Await
调用,代码会阻塞。有没有办法暂停?
答案 0 :(得分:2)
completionTimeout
阶段应该有所帮助。示例如下:
src
.completionTimeout(5.seconds)
...
.run.flatten
.onComplete {
case scala.util.Success(n) => logger.info(s"Created $n movies")
case Failure(t: TimeoutException) => logger.error(t, "Timed out")
case Failure(t) => logger.error(t, "Failed to process movies")
}
文档参考here。